Answer:
12 3/4 same slope fro both
13 DE = 5, CB = 10
14 see below
Step-by-step explanation:
12. the slopes are the same
D(0, 3) E(4, 6) slope is (change in y)/(change in x)
change in y = 3 to 6 is a change of +3
Change in x = 0 to 4 is a change of +4
slope is 3/4
13 To fine lengths you can distance formula or Pythagorean theorem (spoiler: they are related to each other)
DE² = 3² + 4²
DE² = 9 + 12
DE² = 25
√DE² = √25 = 5
DE = 5
and
CB² = 6² + 8²
CB² = 36 + 64
CB² = 100
√CB² = √100 = 10
CB = 10
14. since the slopes are the same are DE is 1/2 or CB its is the mid segment. because (taken from mathopenref.com/trianglemidsegment.html)
The midsegment is always parallel to the third side of the triangle. In the figure above, drag any point around and convince yourself that this is always true.
The midsegment is always half the length of the third side. In the figure above, drag point A around. Notice the midsegment length never changes because the side BC never changes.
A triangle has three possible midsegments, depending on which pair of sides is initially joined.
(1/3+1/2)-(5/6-3/4)=
1/3+1/2-5/6+3/4=
4/12+6/12-10/12+9/12=
10/12-1/12=
9/12=
3/4
Answer:
13x+21
Step-by-step explanation:
20+10x+1+2x+x
Combine like terms.
10x+2x+x+20+1
add.
13x+21
we cannot add those two.
so thats the answer!
13x+21
HOPE I HELPED
PLS MARK BRAINLIEST
DESPERATELY TRYING TO LEVEL UP
✌ -ZYLYNN JADE ARDENNE
JUST A RANDOM GIRL WANTING TO HELP PEOPLE!
PEACE!
<span>6x-2y=-8
-2y =-6x-8
y = 3x+4
y= 3x+4</span>
In a direct variation relationship the values must satisfy that y = kx. This si y is always a constant value (k) times x.
So, you can find multiple values that meet this:
y = kx => k = y / x = 11 / 18
=> y = (11/18)x
Now you can give any value to x and fint the value of x that satisfy the relationship:
x y = (11/18)x
1 11/18
2 11/18 * 2 = 11/9
18 11/18 * 18 = 11
36 11/18 * 36 = 22
So, there you have several additional values for x and y in the same relationship that y = 11 and x = 18, and you can find many more using the same rule: y = (11/18)*x
