Question

6) A sample of water is being cooled according to the formula is given by

Answer 1

Answer:

Relevant domain: [0 40]

Relevant range: [0 80]

Step-by-step explanation:

We have the following function:

$C(t) = 80 - 2t$

In which C(t) is the water temperature.

t is the time.

The colling period ends when the water freezes (0°).

So it freezes after t minutes, and t is found when C(t) = 0. So

$C(t) = 80 - 2t$

$80 - 2t = 0$

$2t = 80$

$t = \frac{80}{2}$

$t = 40$

Relevant domain:

Input value of the function, which is in minutes. So between 0(initial) and 40(when the water freezes).

Relevant range:

Initial temperature, which is C(0) = 80, until it freezes, 0. So from 0 to 80.