Something's not quite right here. What do you mean by "N?"
I could and will make assumptions regarding what you meant. (Feel free to correct me if need be.)
Find the equation of a line through (0,2) <span>which is perpendicular to the line y=3x+3. To find the slope of this perpendicular line, take the negative reciprocal of 3 (the slope of the given line). It is -1/3.
Using the point-slope form of the equation of a straight line:
y = (-1/3)x + 2 (answer)</span>
68% is around 70%
70% of 1 is 0.7
0.7'*3=2.1
Hope this helps :)
Add 1/4a to both sides
-4= 8/4a-3
Simplify
-4=2a-3
Add 3 to both sides
-1=2a
Divide both sides by 2
-1/2=a
Final answer: a=-1/2
Answer:
y - 9 = - 3(x - 2)
Step-by-step explanation:
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
Here m = - 3 and (a, b) = (2, 9), thus
y - 9 = - 3(x - 2) ← in point- slope form
