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ohaa [14]
3 years ago
12

Which elements in the following set are integers -8,3/4,-0.18,0,0.16,5,-2/7,6

Mathematics
1 answer:
aleksklad [387]3 years ago
7 0

Answer:

345

Step-by-step explanation:

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Graphing inequalities in two variables
Pachacha [2.7K]
The solution of a linear inequality in two variables like Ax + By > C is an ordered pair (x, y) that produces a true statement when the values of x and y are substituted into the inequality.
Example
Is (1, 2) a solution to the inequality
2x+3y>1

2⋅1+3⋅2>?1

2+5>?1

7>1

The graph of an inequality in two variables is the set of points that represents all solutions to the inequality. A linear inequality divides the coordinate plane into two halves by a boundary line where one half represents the solutions of the inequality. The boundary line is dashed for > and < and solid for ≤ and ≥. The half-plane that is a solution to the inequality is usually shaded.
Example
Graph the inequality
y≥−x+1

picture44
4 0
3 years ago
Which number rounds to 65.8 when rounded to the nearest tenth
e-lub [12.9K]

Answer:

65.8

Step-by-step explanation:

5 0
3 years ago
What would this answer be??
Nikitich [7]

Answer:

A

Step-by-step explanation:

if the rule is (-x,y) then that just means the x changes

(3,-2) changes to (-3,-2)

4 0
3 years ago
Seventy four point three times <br>five point four​
Marianna [84]

Answer:

401.22

Step-by-step explanation:

5 0
3 years ago
A disadvantage of the contention approach for LANs, such as CSMA/CD, is the capacity wasted due to multiple stations attempting
sammy [17]

Answer:

The overview of the given problem is outlined in the following segment on the explanation.

Step-by-step explanation:

The proportion of slots or positions that have been missed due to numerous concurrent transmission incidents can be estimated as follows:

Checking a probability of transmitting becomes "p".

After considering two or even more attempts, we get

Slot fraction wasted,

= [1-no \ attempt \ probability-first \ attempt \ probability-second \ attempt \ probability+...]

On putting the values, we get

= 1-no \ attempt \ probability-[N\times P\times probability \ of \ attempts]

= 1-(1-P)^{N}-N[P(1-P)^{N}]

So that the above seems to be the right answer.

8 0
4 years ago
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