Answer:
MAG ARAR KA BōBõ
Step-by-step explanation:
MAG ARAR KA BōBõ
Answer:
s(t) = -4.9t² + 39.2t
Step-by-step explanation:
Given the projectile motion of an object can be modeled using s(t) = gt2 + v0t + s0, where g is the acceleration due to gravity, t is the time in seconds since launch, s(t) is the height after t seconds, v0 is the initial velocity, and s0 is the initial height. The acceleration due to gravity is –4.9 m/s²
Given
g = -4.9m/s²
v0 = 39.2m/s
s0 = 0m (the initial height)
On substituting into the formula;
s(t) = gt² + v0t + s0
s(t) = -4.9t² + 39.2t + 0
s(t) = -4.9t² + 39.2t
This gives the equation that models the height
Answer:
Step-by-step explanation:
step 1
In the right triangle ABC
Applying the Pythagoras Theorem fin the hypotenuse AC
substitute
step 2
we know that
If two figures are similar, then the ratio of its corresponding sides is equal
so
substitute and solve for CE
step 3
Find the length of segment AE
AE=AC+CE
substitute the values
The quotient of z and 3.
quotient = ÷
z/3
The answer is A.
