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3 years ago

HELP PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

MakcuM [25]3 years ago

4 0

Answer:

Step-by-step explanation:

Arc GHJ is 81*2= 162 (the arc measure of an inscribed angle that does not cross the center of the circle is 2 times the measure of the angle

since arc GH is 84 and we need HJ, subtract 84 from 162=78

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Prove: Quadrilateral ABCD is a parallelogram.

Brilliant_brown [7]

Answer:

Step 3.

m∠ AEB = m∠ CED .........By Vertical Angles Theorem.

Step-by-step explanation:

Vertical Angles Theorem:

Vertical angle theorem states that vertical angles, angles that are opposite each other and formed by two intersecting lines,are congruent.

If two lines intersect each other we have two pair of vertical opposite angles. As shown in the figure.

Here,

∠ 1 and ∠ 2 are vertical opposite angles and also they are equal.

∠ 3 and ∠ 4 are also vertical opposite angles and also they are equal.

For,

step 3. m∠ AEB = m∠ CED

Therefore, the reason for step 3 of this proof is Vertical Angles Theorem.

6 0

3 years ago

I need help with 3 questions! In attachments............. 1 done

aev [14]

Hello the correct answer is d have a great one

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3 years ago

Solve the inequality for x 3^(6x+18)<27^(3x)

Lera25 [3.4K]

Answer:

$\displaystyle x > 6$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients
Factoring

Algebra II

Exponential Rule [Powering]: $\displaystyle (b^m)^n = b^{m \cdot n}$
Solving exponential equations

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle 3^{6x + 18} < 27^{3x}$

Step 2: Solve for x

Rewrite: $\displaystyle 3^{6x + 18} < 3^{3(3x)}$
Set: $\displaystyle 6x + 18 < 3(3x)$
Factor: $\displaystyle 3(2x + 6) < 3(3x)$
[Division Property of Equality] Divide 3 on both sides: $\displaystyle 2x + 6 < 3x$
[Subtraction Property of Equality] Subtract 3x on both sides: $\displaystyle -x + 6 < 0$
[Subtraction Property of Equality] Subtract 6 on both sides: $\displaystyle -x < -6$
[Division Property of Equality] Divide -1 on both sides: $\displaystyle x > 6$