Answer:
16.5 g of CO₂ are produced by 18.5 of methane and 24 g of O₂
Explanation:
This is a reaction of combustion:
CH₄ + 2O₂ → CO₂ + 2H₂O
1 mol of methane react to 2 moles of oxygen in order to produce 1 mol of carbon dioxide and 2 moles of water.
First of all, we determine the moles of each reactant:
18.5 g . 1mol/ 16g = 1.15 moles of methane
24 g . 1mol / 32g = 0.75 moles of oxygen
Now, we determine the limiting reactant:
1 mol of methane reacts to 2 moles of oyxgen
1.15 moles of methane may react to (1.15 . 2) /1 = 2.3 moles.
We only have 0.75 moles of O₂ and we need 2.3, that's why the oxygen is the limiting reagent, because we do not have enough oxygen for the reaction.
2 moles of O₂ produce 1 mol of CO₂
Then 0.75 moles may produce (0.75 . 1) /2 = 0.375 moles of CO₂
We convert the moles to mass → 0.375 mol . 44g /mol = 16.5 g
