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S_A_V [24]
3 years ago
15

What is the frequency, in hertz, of an electromagnetic wave with a wavelength of 625 nm?

Chemistry
1 answer:
Reika [66]3 years ago
6 0

Answer:- Frequency is 4.80*10^1^4Hz .

Solution:- The wavelength of electromagnetic radiation is given as 625 nm and we are asked to calculate the frequency. Frequency is inversely proportional to the wavelength and the formula used to calculate frequency when wavelength is given is:

\nu =\frac{c}{\lambda }

where, \nu is frequency, c is speed of light and \lambda is the wavelength.

Value of speed of light is \frac{3.0*10^8m}{s} . We need to convert the given wavelength from nm to m.

1nm=10^-^9m

So, 625nm(\frac{10^-^9m}{1nm})

= 6.25*10^-^7m

Let's plug in the values in the formula and calculate the frequency:

\nu =\frac{3.0*10^8m.s^-^1}{6.25*10^-^7m}

= 4.80*10^1^4s^-^1 or Hz.

So, the frequency of the electromagnetic wave is 4.80*10^1^4Hz .

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For+the+reaction+H2+++I2+-+2HI+the+equilibrium+constant,+kc+is+49+at+a+fixed+temperature.+Two+mole+of+hydrogen+and+two+moles+of+
Sonja [21]

Answer : The initial concentration of HI and concentration of HI at equilibrium is, 0.27 M and 0.386 M  respectively.

Solution :  Given,

Initial concentration of H_2 and I_2 = 0.11 M

Concentration of H_2 and I_2 at equilibrium = 0.052 M

Let the initial concentration of HI be, C

The given equilibrium reaction is,

    H_2(g)+I_2(g)\rightleftharpoons 2HI(g)

Initially               0.11   0.11            C

At equilibrium  (0.11-x) (0.11-x)   (C+2x)

As we are given that:

Concentration of H_2 and I_2 at equilibrium = 0.052 M  = (0.11-x)

The expression of K_c will be,

K_c=\frac{[HI]^2}{[H_2][I_2]}

54.3=\frac{(C+2(0.058))^2}{(0.052)\times (0.052)}

By solving the terms, we get:

C = 0.27 M

Thus, initial concentration of HI = C = 0.27 M

Thus, the concentration of HI at equilibrium = (C+2x) = 0.27 + 2(0.058) = 0.386 M

3 0
3 years ago
Which of the following is true about neutrons?
Alja [10]
D is the only choice here that is appropriate given neutrons' lack of charge
5 0
3 years ago
Will mark brainliest!!
olga2289 [7]

Answer:

I think its B im not sure

but i hope this helps

6 0
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9. Circle the atom in each pair that has the greater ionization energy.
Sedbober [7]
A: BE has more ionization energy than LI

B: CA has more ionization energy than BA.
C: NA has more ionization energy than K

D: AR has more ionization energy than P

E: CI has a more ionization energy than SI
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If any of these are wrong feel free to correct me in the comments.
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Question # 10
satela [25.4K]
The answer should be D, cells can only create an identical copy of the original cell.
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