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S_A_V [24]
3 years ago
15

What is the frequency, in hertz, of an electromagnetic wave with a wavelength of 625 nm?

Chemistry
1 answer:
Reika [66]3 years ago
6 0

Answer:- Frequency is 4.80*10^1^4Hz .

Solution:- The wavelength of electromagnetic radiation is given as 625 nm and we are asked to calculate the frequency. Frequency is inversely proportional to the wavelength and the formula used to calculate frequency when wavelength is given is:

\nu =\frac{c}{\lambda }

where, \nu is frequency, c is speed of light and \lambda is the wavelength.

Value of speed of light is \frac{3.0*10^8m}{s} . We need to convert the given wavelength from nm to m.

1nm=10^-^9m

So, 625nm(\frac{10^-^9m}{1nm})

= 6.25*10^-^7m

Let's plug in the values in the formula and calculate the frequency:

\nu =\frac{3.0*10^8m.s^-^1}{6.25*10^-^7m}

= 4.80*10^1^4s^-^1 or Hz.

So, the frequency of the electromagnetic wave is 4.80*10^1^4Hz .

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In mechanics, speed increase is the pace of progress of the speed of an article regarding time (acceleration). Speed increases are vector amounts (in that they have greatness and direction). The direction of an item's speed increase is given by the direction of the net power following up on that article. The size of an item's speed increase, as depicted by Newton's Second Law, is the consolidated impact of two causes:

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2 years ago
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What is the answer please
xeze [42]

Answer:

Selenium

Explanation:

Oxygen is present in the group sixteen.

This group consist of oxygen, sulfur, selenium, tellurium and polonium.

All of these have same number of valance electrons thus they show similar properties.

From the given list of elements only selenium is belong to oxygen family thus it has properties similar to the oxygen.

Electronic configuration of oxygen:

O = [He] 2s² 2p⁴

Electronic configuration of selenium:

Se = [Ar] 3d¹⁰ 4s² 4p⁴

While aluminium, boron and phosphorus are belongs to other groups that's why their properties are not similar to the phosphorus.

phosphorus is present in group 15.

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6 0
3 years ago
A water treatment plant receives the source water with an average Ca2+ concentration of 46.9 mg/L and Mg2+ concentration of 14.8
Veronika [31]

Answer:

42,650 kg of calcium carbonate will be produced everyday.

13,600.5 kg of magnesium hydroxide will be produced everyday.

Explanation:

Concentration of calcium ions = 46.9 mg/L

Concentration of magnesium ions = 14.8  mg/L

Volume of solution treated everyday , V= 80 million gal

= 80\times 10^6 gal=4.546\times 80\time 10^6 L=3.637\times 10^8 L

1 gallon = 4.546 Liter

Mass of  calcium ion in V = 46.9 mg/L\times 3.637\times 10^8 L

=  1.706\times 10^{10} mg

1 mg = 0.001 g

1.706\times 10^{7} g

Moles of calcium ions = \frac{1.706\times 10^{7} g}{40 g/mol}=426,500 mol

From 1 mole of calcium ion 1mol of carbonate is formed . then from 426,500 moles of calcium ion will form :

\frac{1}{1}\times 426,500 mol=426,500 mol of calcium carbonate

Mass of 426,500 moles of calcium carbonate:

426,500 mol × 100 g/mol  = 42,650,000 g = 42,650 kg

Mass of  magnesium ion in V = 14.8 mg/L\times 3.637\times 10^8 L

= 5.382\times 10^{9} mg

=  5.382\times 10^{6} g

Moles of magnesium ions = \frac{5.382\times 10^{6} g}{24 g/mol}=224,250 mol

From 1 mole of magnesium ion 1 mol of magnesium hydroxide is formed . then from 224,250 moles of magnesium ion will form :

\frac{1}{1}\times 224,250 mol=224,250 mol of magnesium hydroxide

Mass of 224,250 moles of magnesium hydroxide:

224,250 mol × 58 g/mol  = 13,006,500 g = 13,006.5 kg

42,650 kg of calcium carbonate will be produced everyday.

13,600.5 kg of magnesium hydroxide will be produced everyday.

3 0
3 years ago
In this cell amino acid molecules combine to form
BaLLatris [955]

Answer:

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To form polypeptides and proteins, amino acids are joined together by peptide bonds, in which the amino or NH2 of one amino acid bonds to the carboxyl (acid) or COOH group of another amino acid.

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