All categories

2 years ago

Help im not good with fractions!!!

Mathematics

2 answers:

nata0808 [166]2 years ago

7 0

Answer:

2 please follow me fast and vote me

Step-by-step explanation:

2/3*3

= 6/3

= 2

almond37 [142]2 years ago

4 0

2/9 because I know that’s it

You might be interested in

Brandon and his children went into a bakery and where they sell donuts for $1.25

barxatty [35]

Answer:

Step-by-step explanation:

Since cookies are $.25 each, and Brandon purchased only 2, you can conclude he has already spent $.50.

If you deduct that from the total, $5.50, you have $5 left. Divide the cost of the donuts, $1.25, and the total to get the answer of 4.

3 0

2 years ago

Read 2 more answers

5 divided by 39.5 please awnser

adell [148]

the answer to 5 divided by 39.5 is 0.127

6 0

2 years ago

Nolan just drove at a constant rate for 5 hours. He is now 340 miles from where he started. At what rate was he driving? Nolan h

Sauron [17]

Answer:

68 miles

3 hours

Step-by-step explanation:

340/5=68

204/68=3

7 0

2 years ago

Triangle RST is rotated 180° about the origin, and then translated up 3 units. Which congruency statement describes the figures?

Mazyrski [523]

Answer: ΔRST ≅ ΔBAC

Step-by-step explanation:

We know that To rotate a figure 180 degrees, you will need to apply the rule (x, y) → (-x, -y).

Thus, The coordinates of Δ RST becomes

R (1,1) → R'(-1,-1)

S (3,4) → S'(-3,-4)

T(-5,0) → T'(5,0)

Also ΔRST after rotation is translated up 3 units. , so we apply the rule (x,y)→(x,y+3)

R'(-1,-1)→R"(-1,-1+3)=R"(-1,2)→ B

S'(-3,-4) → S"(-3,-4+3) = R"(-3,-1) → A

C'(-5,0) → C"(-5,0+3) → C"(-5,3) → C

As rotation and translation both are rigid transformation that maps only congruent figures.

Therefore, ΔRST ≅ Δ BAC

7 0

3 years ago

Read 2 more answers

fire work a travels at the speed 300 ft/s firework b travels 240 ft/s. firework b is launched 0.25s before firework a. how many

storchak [24]

Answer:

Both fireworks will explode after 1 seconds after firework b launches.

Step-by-step explanation:

Given:

Speed of fire work A= 300 ft/s

Speed of Firework B=240 ft/s

Time before which fire work b is launched =0.25s

To Find:

How many seconds after firework b launches will both fireworks explode=?

Solution:

Let t be the time(seconds) after which both the fireworks explode.

By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation

Firework A= 330(t)

Firework B=240(t)+240(0.25)

Since we need to know the same time after which they explode, we can equate both the equations

330(t) = 240(t)+240(0.25)

300(t)= 240(t)+60

300(t)-240(t)= 60

60(t)=60

$t=\frac{60}{60}$

t=1

7 0

2 years ago