Answer:
2 units is perpendicular bisector of line segment
Answer:
5 units
Step-by-step explanation:
Let point O be the point of intersection of the kite diagonals.
|OF| = 2, |OH| = 5
|FH| = |OF| + |OH| = 2 + 5 = 7
FH and EG are the diagonals of the kite. Hence the area of thee kite is:
Area of kite EFGH = (FH * EG) / 2
Substituting:
35 = (7 * |EG|) / 2
|EG| * 7 = 70
|EG| = 10 units
The longer diagonal of a kite bisects the shorter one, therefore |GO| = |EO| = 10 / 2 = 5 units
x = |GO| = |EO| = 5 units
Answer:
A and B are correct
Step-by-step explanation:
Answer:
56
Step-by-step explanation:
8 times 7=56
Answer:
50 cm
Step-by-step explanation:
So the first step is to find the height, and to do that you know that the area of a triangle is height * base / 2 = area. Plugging in the numbers you have, you get:

Then, this becomes

Divide both sides by 24

Now you can use the base and the height to find the hypotenuse using the Pythagorean Theorem: 

Therefore the length of the hypotenuse is 50 cm