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2 years ago

PLEASE HELP ASAP!!!

Mathematics

1 answer:

grigory [225]2 years ago

8 0

Answer:

1.)10 2.)0 3.)10

Step-by-step explanation:

1.) 4 (2) = 8 + 2 = 10

2.) 2(2) - 4/5 = 0

3.)2y + 11/-11 = +3y/-3y +1

2y - 3y = 1 - 11

-1y/-1 = -10/-1 = 10

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Given segments AB and CD intersect at E.

nata0808 [166]

The length of a segment is the distance between its endpoints.

$\mathbf{AB = 3\sqrt{2}}$
AB and CD are not congruent
AB does not bisect CD
CD does not bisect AB

(a) Length of AB

We have:

$\mathbf{A = (1,2)}$

$\mathbf{B = (4,5)}$

The length of AB is calculated using the following distance formula

$\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

So, we have:

$\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}$

$\mathbf{AB = \sqrt{18}}$

Simplify

$\mathbf{AB = 3\sqrt{2}}$

(b) Are AB and CD congruent

First, we calculate the length of CD using:

$\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

Where:

$\mathbf{C = (2, 4)}$

$\mathbf{D = (2, 1)}$

So, we have:

$\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}$

$\mathbf{CD = \sqrt{9}}$

$\mathbf{CD = 3}$

By comparison

$\mathbf{CD \ne AB}$

Hence, AB and CD are not congruent

(c) AB bisects CD or not?

If AB bisects CD, then:

$\mathbf{AB = \frac 12 \times CD}$

The above equation is not true, because:

$\mathbf{3\sqrt 2 \ne \frac 12 \times 3}$

Hence, AB does not bisect CD

(d) CD bisects AB or not?

If CD bisects AB, then:

$\mathbf{CD = \frac 12 \times AB}$

The above equation is not true, because:

$\mathbf{3 \ne \frac 12 \times 3\sqrt 2}$

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

7 0

3 years ago

ASAP someone please simply two exponents

zhannawk [14.2K]

Answer:

1.) $m^{15}$

2.) $=\frac{1}{y^{15}}$

Give me a comment if you want the explanation.

1.) $\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0$

$\left(m^3\right)^5=m^{3\cdot \:5}$

$\mathrm{Multiply\:the\:numbers:}\:3\cdot \:5=15$

$=m^{15}$

2.) $\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0$

$\left(y^{-3}\right)^5=y^{-3\cdot \:5}$

$=y^{-3\cdot \:5}$

$=y^{-15}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}$

$=\frac{1}{y^{15}}$

4 0

3 years ago

Plz help ASAP I don’t know just tell me the Awnser plz ASAP

Ann [662]

Answer:

The experimental probability is 1/6

Step-by-step explanation:

WIN = 8/48

= 1/6 or 0.1667 = 16.67% chance of winning

LOSE = 40/48

= 5/6 or 0.8333 = 83.33% chance of losing.

I hope this helps. ;)

5 0

3 years ago

Noam's bank account showed -$70 and Ben's bank account showed -$93. Who owes more money?

Mrac [35]

ben owes more money since he has a debt of $ 93 and noam had a debt of only $ 70

hope that helps !

5 0

3 years ago

Hhhhhhhhhheeeeeeeeeeeeeeeeeeeeeeeeelllllllllllllllpppppppppppppppppppppp

loris [4]

Remember that both the denominator and the square root function cannot have values less than 0. So to figure what values can go into each we need to do a little math. Set both the denominator and the under the radical equal to 0
x + 2 = 0 x - 3 = 0
x = -2 x = 3

Since they must be those numbers or bigger 3 is the larger of the 2 the final answer is
x >= 3 Type in greater than into the box

7 0

3 years ago