Complete Question
The length of the guy wire supporting a cell tower is 120 m. The guy wire is anchored to the ground at a distance of 80 m from the base of the tower to the nearest hundredth of a meter how tall is the tower?
Answer:
89.44m
Step-by-step explanation:
We solve this question using the Pythagoras Theorem
This is given as:
Hypotenuse² = Opposite ² + Adjacent ²
Hypotenuse = Length of the guy wire = 120m
Adjacent = Distance from the base of the tower = 80m
Opposite = Height of the building = x
Hence:
120² = x² + 80²
Collect like terms
x² = 120² - 80²
x = √120² - 80²
x = √(8000)
x = 89.4427191 m
Approximately the height of the tower is = 89.44m
Answer:
We have (2/3)x(1-1/4) - 1/4 = (2/3)x(3/4) -1/4 = 6/12 = 1/4 = 1/2 -1/4 = 2/4 - 1/4 = 1/4 do I bring in between;
Step-by-step explanation:
292in^3
3x6x10=180 because I’ve split the shape in half
7x4x4=112
180+112=292
Answer:
Rs 120
Step-by-step explanation:
Let MP = m
Discount = 25% of MP = m/4
SP = MP - Discount
= m - m/4 = 3m/4
If profit is 20%, CP = 3m/4 x 100/120 = 5m/8
=> Profit = 3m/4 - 5m/8 = m/8
Given Profit - Discount = Rs 15
=> |m/8 - m/4| = 15
m/8 = 15
m = Rs 120
Answer:
2m+2=16, then do the isolate m but doing the inverse operation of 2 which is now -2 and add that to 16 would be left with 2m=14 and 14/2 is 7 so m=7
Step-by-step explanation:
