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DiKsa [7]
3 years ago
13

This is a quiz on special right triangles. please help me i cannot fail this. i will mark brainliest

Mathematics
1 answer:
kobusy [5.1K]3 years ago
4 0

Answer:

x=4

Step-by-step explanation:

Consider ΔKLJ:

sinθ=opposite/hypotenuse

sin30=LJ/8√2

LJ=0.5*8√2=4√2

Consider ΔMLJ:

sinθ=opp/hyp

sin45=x/4√2

1/√2=x/4√2

4√2/√2=x

x=4

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You didnt provide the selections, but some answers would most likely be rotations, translations, and reflections.
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Rita earns $10 per hour. She puts 5% of her earnings in savings. Write inequality to find how many hours Rita must work to save
Rina8888 [55]

Answer:

Rita must work 50 days  to save at least $25.

Step-by-step explanation:

The amount Rita earns per hour  = $10

The saving percentage =  5%

So, the savings of Rita per hour =  5% of $10

⇒5% of $10  = \frac{5}{100}  \times 10  = 0.5

or Rita saves $0.5 per hour.

The amount she wants to save at minimum  = $25

So, let she works at the minimum of k Days.

⇒\textrm{The number of hours she has to work}  = \frac{\textrm{Amount she needs saving}}{\textrm{Amount saved in 1 hour}}

or, k = \frac{25}{0.5}  = 50

The number of hours she has to work  =  50 days

Hence,  Rita must work 50 days  to save at least $25.

3 0
3 years ago
Can someone help me <br> Please and thank you!!
Arada [10]

Answer:

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Step-by-step explanation:

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What is the slope of the line passing through (-3, 5) and (5,-3)?
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A student solves the following equation and
Phoenix [80]

Answer:

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

Step-by-step explanation:

Considering the expression

\frac{3}{a+2}-6\cdot \frac{a}{-4+a^2}=\frac{1}{a-2}

\frac{3}{a+2}-\frac{6a}{-4+a^2}=\frac{1}{a-2}

\mathrm{Find\:Least\:Common\:Multiplier\:of\:}a+2,\:-4+a^2,\:a-2:\quad \left(a+2\right)\left(a-2\right)

\mathrm{Multiply\:by\:LCM=}\left(a+2\right)\left(a-2\right)

\frac{3}{a+2}\left(a+2\right)\left(a-2\right)-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right)=\frac{1}{a-2}\left(a+2\right)\left(a-2\right)

as

  • \frac{3}{a+2}\left(a+2\right)\left(a-2\right):\quad 3\left(a-2\right)
  • -\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right):\quad -6a
  • \frac{1}{a-2}\left(a+2\right)\left(a-2\right):\quad a+2

so equation becomes

3\left(a-2\right)-6a=a+2  

-3a-6=a+2

-3a-6+6=a+2+6

-4a=8

\mathrm{Divide\:both\:sides\:by\:}-4

\frac{-4a}{-4}=\frac{8}{-4}

a=-2

\mathrm{Verify\:Solutions}

\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{3}{a+2}-6\frac{a}{-4+a^2}-\frac{1}{a-2}\mathrm{\:and\:compare\:to\:zero}

\mathrm{Solve\:}\:a+2=0:\quad a=-2

\mathrm{Solve\:}\:-4+a^2=0:\quad a=2,\:a=-2

\mathrm{Solve\:}\:a-2=0:\quad a=2

So the following points are undefined

a=-2,\:a=2

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

4 0
3 years ago
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