Answer:
(x+3)(x+4)(x-4)
x+2 and x-3 are not factors but x-4 is
Step-by-step explanation:
let's factor it :)
x^3 + 3x^2 - 16x -48
first we will factor this:
x^3 + 3x^2
x^2(x + 3)
then factor the second part :
- 16x - 48
-16(x + 3)
so now,
x^2(x + 3) - 16(x + 3)
factor out x+3
(x+3)(x^2 - 16)
factor x^2 - 16
(x+3)(x+4)(x-4)
Answer:
120
Step-by-step explanation:
you are multiping you are trying to get the number of the base
Answer:
1155
Step-by-step explanation:
Y=|-1|-4
The absolute value of -1 is 1
y=1-4
y=-3
Answer:
<h2>49</h2>
Step-by-step explanation:
Use PEMDAS:
P Parentheses first
E Exponents (ie Powers and Square Roots, etc.)
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)
==============================================
(-5)² - 2 × (-9) + 6 <em>first </em><em>E</em><em>xponents</em>
25 - 2 × (-9) + 6 <em>next </em><em>M</em><em>ultiplication</em>
25 + 18 + 6 <em>next </em><em>A</em><em>ddition</em>
43 + 6 = 49