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Fantom [35]
3 years ago
14

There’s 2 answer options

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
8 0

Answer:

yes their just 2 answer choices

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For number 6, evaluate the definite integral.
maks197457 [2]
\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{(8+2x)^2}}\cdot dx\impliedby \textit{now, let's do some substitution}\\\\
-------------------------------\\\\
u=8+2x\implies \cfrac{du}{dx}=2\implies \cfrac{du}{2}=dx\\\\
-------------------------------\\\\

\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{u^2}}\cdot \cfrac{du}{2}\implies \cfrac{1}{2}\int\limits_{0}^{28}\ u^{-\frac{2}{3}}\cdot du\impliedby 
\begin{array}{llll}
\textit{now let's change the bounds}\\
\textit{by using } u(x)
\end{array}\\\\
-------------------------------\\\\
u(0)=8+2(0)\implies u(0)=8
\\\\\\
u(28)=8+2(28)\implies u(28)=64

\bf \\\\
-------------------------------\\\\
\displaystyle  \cfrac{1}{2}\int\limits_{8}^{64}\ u^{-\frac{2}{3}}\cdot du\implies \cfrac{1}{2}\cdot \cfrac{u^{\frac{1}{3}}}{\frac{1}{3}}\implies \left. \cfrac{3\sqrt[3]{u}}{2} \right]_8^{64}
\\\\\\
\left[ \cfrac{3\sqrt[3]{(2^2)^3}}{2} \right]-\left[ \cfrac{3\sqrt[3]{2^3}}{2}  \right]\implies \cfrac{12}{2}-\cfrac{6}{2}\implies 6-3\implies 3
3 0
3 years ago
What is the product of 1/2x-1/4 and 5^2-2x+6 <br> Show work please need an answer fast
kaheart [24]
1/8 for the first one and second one is 23 times 6

7 0
3 years ago
Read 2 more answers
Solve for j<br> 9j=19+8j
charle [14.2K]

Answer: The answer would be j=19

6 0
3 years ago
Read 2 more answers
How to solve please help thank you
Rashid [163]

her new balance is $105.

hope this helps.

7 0
3 years ago
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Apply the distributive property to create an equivalent expression. (1-2g+4h)x5
kifflom [539]

Answer: 5-10g+20h

Step-by-step explanation:

You can rewrite as 5(1-2g+4h). 5x1 equals 5, 5x2g=10g, 5x4h=20h, then you get 5-10g+20h

-viridiancat4, an 8th grader! :)

8 0
3 years ago
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