Question

In ΔOPQ, o = 500 cm, p = 600 cm and q=380 cm. Find the measure of ∠P to the nearest 10th of a degree.

Answer 1

The measure of ∠P to the nearest 10th of a degree is 84.8°

Law of Cosines

From the question, we are to determine the measure of ∠P

From the law of cosines, we can write that

$cos \ P=\frac{o^{2}+q^{2}-p^{2} }{2oq}$

From the given information,

o = 500 cm

p = 600 cm

q = 380 cm

Putting the parameters into the formula, we get

$cos \ P=\frac{500^{2}+380^{2}-600^{2} }{2\times 500 \times 380}$

$cos \ P =\frac{34400}{380000}$

$cos \ P =0.0905$

P = cos⁻¹(0.0905)

P = 84.8076

P ≅ 84.8°

Hence, the measure of ∠P to the nearest 10th of a degree is 84.8°

Learn more on the Law of Cosines here: brainly.com/question/20890746

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