Answer:
Domain = {All real values of x EXCEPT x = -5 and x = 7}
Step-by-step explanation:
This is a rational function given as y=\frac{6+9x}{6-|x-1|}y=
6−∣x−1∣
6+9x
The domain is the set of all real value of x for which the function is defined.
For rational functions, we need to find which value of x makes the denominator equal to 0. We need to exclude those values from the domain.
Now
6 - |x-1| = 0
|x-1| = 6
x- 1 = 6
or
-(x-1) = 6
x = 6+1 = 7
and
-x+1=6
x = 1-6 = -5
So, the x values of -5 and 7 makes this function undefined. So the domain is the set of all real numbers except x = -5 and x = 7
Answer:
I think that the equation would be Y= -2X^2-4X-4 .
Step-by-step explanation:
Hope it wad helpful :)
|3+10|=|3|+|10|
|13|=|13|
13=13
Answer:
f(g(x)) = 15x + 2
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Distributive Property
<u>Algebra I</u>
- Functions
- Function Notation
- Composite Functions
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
f(x) = 5x + 7
g(x) = 3x - 1
<u>Step 2: Find</u>
- Substitute in functions: f(g(x)) = 5(3x - 1) + 7
- [Distributive Property] Distribute 5: f(g(x)) = 15x - 5 + 7
- [Addition] Combine like terms: f(g(x)) = 15x + 2
