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Marysya12 [62]
2 years ago
11

A stack of 150 pieces of paper is 2.5 cm thick how many pieces of paper are in a pile 6.5 CM thick​

Mathematics
1 answer:
umka21 [38]2 years ago
5 0

Find the scale factor of the height:

6.5cm / 2.5cm = 2.6

Multiply the known pages by the scale factor:

150 x 2.6 = 390 pieces of paper.

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The value of x-y is negative, and x and y are both positive. What can you conclude about the values of x
Stolb23 [73]
Well for two positive numbers subtracted to equal a negative number, the first number must have a value that is less than the second number. (Ex. 3-4= -1) In this case, you can conclude that x is less than y! (x<y)
3 0
3 years ago
What is the solution to this equation?<br>1-2x = 4(x + 3)​
valina [46]

Answer:

x=-1.83

Step-by-step explanation:

1-2x=4(x+3)

1-2x=4x+12

-2x=4x+12-1

-2x=4x+11

-2x-4x=11

-6x=11

x=11÷-6

x=-1.83

4 0
2 years ago
Hiroto spends \$68 on e-books and paperback books combined. Each e-book he buys costs $5 and each paperback book he buys costs $
alina1380 [7]

The equation that can be used to model the situation regarding the e-books and paperback is 5x + 12y = 68

The following information can be gotten from the question:

Total amount spent on e-books and paperback = $68

<em>Cost</em><em> of e-book = $5 each.</em>

<em>Cost of paperback = $12 each</em>

<em>Number of</em><em> e-books</em><em> = x</em>

<em>Number of paperbacks = y</em>

Therefore, the equation that can be used to model the situation regarding the <em>e-books </em>and <em>paperback</em> will be:

= 5(x) + 12(y) = 68

5x + 12y = 68

The equation will be 5x + 12y = 68

Read related link on:

brainly.com/question/25212173

5 0
2 years ago
Determine
mihalych1998 [28]

Answer:

=4.+2.

Step-by-step explanation:

<u>Linear Combination Of Vectors </u>

One vector \vec b is a linear combination of \vec a_1 and \vec a_2 if there are two scalars x_1, x_2 such as

\vec b=x_1\vec a_1+x_2\vec a_2

In our case, all the vectors are given in R^3 but there are only two possible components for the linear combination. This indicates that only two conditions can be used to determine both scalars, and the other condition must be satisfied once the scalars are found.

We have

\vec a_1=,\ \vec a2=,\ \vec b=

We set the equation

=x_1.+x_2.

Multiplying both scalars by the vectors

=+

Equating each coordinate, we get

4x_1-4x_2=8

5x_1+3x_2=26

-4x_1+3x_2=-10

Adding the first and the third equations:

-x_2=-2

x_2=2

Replacing in the first equation

4x_1-4(2)=8

4x_1=8+8

x_1=4

We must test if those values make the second equation become an identity

5(4)+3(2)=20+6=26

The second equation complies with the values of x_1 and x_2, so the solution is

=4.+2.

8 0
3 years ago
Solve for n in the literal equation a(n-2)+5=bn
Helga [31]

Answer:

<u><em>Answer is below</em></u>

Step-by-step explanation:

<em><u>a(n-2)+5=bn</u></em>

<em><u>Add -bn to both sides</u></em>

<em><u>an-2a+5+(-bn)=bn+(-bn)</u></em>

<em><u>an-bn-2a+5=0</u></em>

<em><u>add two a to both sides</u></em>

<em><u>an−bn−2a+5+(2a)=0+(2a)</u></em>

<em><u>an−bn+5=2a</u></em>

<em><u>Add -5 to both sides</u></em>

<em><u>an−bn+5+(-5)=2a+(-5)</u></em>

<em><u>an−bn=2a−5</u></em>

<em><u>Factor out our variable</u></em>

<em><u>n(a−b)=2a−5</u></em>

<em><u>Divide both sides by a-b</u></em>

<em><u>n(a-b)/a-b=2a-5/a-b</u></em>

<em><u>n=2a-5/a-b</u></em>

<em><u>Hope this helps</u></em>

7 0
3 years ago
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