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IgorLugansk [536]
3 years ago
5

Suppose a Pony Express rider was paid $192 for 12 weeks of work. If he was paid the same amount each week,how much was he paid f

or 3 weeks of work?
Mathematics
1 answer:
Masteriza [31]3 years ago
5 0
$192 divided by 12 is 16 so 16 x 3 is 48. That is your answer $48. Your welcome bud.
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What can k equal so that 2kx-3k<2x+4+3kx to have no solution
const2013 [10]
Answer: k = -2
solution: 2kx-3k<2x+4+3kx,
-3k-4<2x+3kx-2kx,
-3k-4<(k+2)x
Since this inequality has no solution, k = -2.
3 0
3 years ago
The front wall of the storage shed is in the shape of a trapezoid.
KonstantinChe [14]

Answer:

66 square feet

Step-by-step explanation:

please review the attachment for a detailed explanation

7 0
3 years ago
Karen is writing a word problem that can be represented by the equation 3x + 2 = 20. A box weighs 3 pounds and several 2 pound b
inna [77]
No because the box has a fixed weight as the several books weighing said pounds would most likely to be use as the x in this equation.
3 0
3 years ago
Find the angle of elevation of the sun from the ground to the top of a tree when a tree that is 10 yards tall casts a shadow 14
Hitman42 [59]

Answer:

The angle of elevation of the sun from the ground to the top of a tree is 36^{\circ}.

Step-by-step explanation:

As given

The sun from the ground to the top of a tree when a tree that is 10 yards tall casts a shadow 14 yards long.

Now by using the trignometric identity .

tan\theta =\frac{Perpendicular}{Base}

As figure is  given below .

AB =  Perpendicular = 10 yards

BC =  Base = 14 yards

Putting all the values in the trignometric identity .

tan\theta =\frac{AB}{BC}

tan\theta =\frac{10}{14}

\theta =tan^{-1}(\frac{10}{14})

\theta =36^{\circ}

Therefore the angle of elevation of the sun from the ground to the top of a tree is 36^{\circ}.

7 0
3 years ago
Read 2 more answers
If a is an integer, which of the 
sweet [91]
So to work this out we need to find the 4th root of each of those and pick the one that gives an integer.

A: \sqrt[4]{1.6*10^1^1} = 632.455... This is a decimal therefore <em>not</em> an integer.

B: \sqrt[4]{1.6*10^1^2} =1124.682... Again a decimal, therefore <em>not </em>an integer.

C: \sqrt[4]{1.6*10^1^3} =2000 This is a whole number, so it <em>is </em>an integer.

D: \sqrt[4]{1.6*10^1^4} =3556.558... Decimal, therefore <em>not </em>an integer

E: \sqrt[4]{1.6*10^1^5} =6324.555... Again a decimal, <em>not</em> an integer.

The only one that gives an integer when put to the 4th root is C, therefore:

1.6*10^1^3 could be A^4, as the 4th root of it is an integer.

5 0
3 years ago
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