Answer:
The class width is 20
Step-by-step explanation:
In a frequency or a relative frequency distribution the class width is calculated as the difference between the lower or upper class limits of consecutive classes. A point to note is that all the categories or classes usually have the same class width.
We use the first two classes to calculate the class width by using their respective upper limits;
Class width = 89 - 69
Class width = 20
Answer:
A is (10,0)
B is (3, 3).
Step-by-step explanation:
First we calculate the coordinates of the point A.
Here, y = 0 so we have:
7(0) - 3x + 30 = 0
-3x + 30 = 0
x = -30/-3 = 10.
So A has coordinates (10,0).
Next we find the coordinates of the points where the line passes through the y axis. Here x = 0:
7x - 3(0) = 30
x = 30/7.
So the point is (0, 30/7).
Let the point B have coordinates (x1, y1)
Now x1 = y1 (given).
If we draw a line from B perpendicular to the x axis ( its length will be = y1) then we have 2 similar triangles.
So as corresponding sides are in the same ratio:
y1/ (30/7) = (10-x1) / 10
But as x1 = y1:
x1/ (30/7) = (10-x1) / 10
7 x1 / 30 = (10-x1) / 10
70 x1 = 30(10 - x1)
70x1 = 300 - 30 x1
100 x1 = 300
x1 = 3
So the coordinates of B are (3,3)
Checking the solution to the equation:
LHS = 3 / 30/7 = 3*7 / 30 = 21/30 = 7/10.
RHS = (10 -3 ) / 10 = 7/10.
Multiply the dust particle mass by 5 billion..
On a calculator use the "EE" button is shorthand for: x10^ whatever power you want.
5x10^9 x 7.53x106-10 = 3.765
Answer:
Nine more than the number of cars would be c+9