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HACTEHA [7]
4 years ago
15

Urgent! Help, please!

Mathematics
2 answers:
AfilCa [17]4 years ago
7 0
TW = SW  so

2x + 2 = 4x - 12
14 = 2x

x = 7 Answer
daser333 [38]4 years ago
5 0

Answer:

TW = SW  so

2x + 2 = 4x - 12

14 = 2x

x = 7 Answer

Step-by-step explanation:

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What's -18÷(1-4+-2-4) explain pls need help​
Mrac [35]

Answer:

the answer is 2.

Step-by-step explanation:

i dont know how to explain sorry

4 0
3 years ago
Solve the following system of equations for a and for b:
viktelen [127]

Answer:

a=3\\b=1

Step-by-step explanation:

9a+3b=30\\8a+4b=28

Let's solve the second equation for a to later on replace it in the first equation.

8a+4b=28\\8a=28-4b\\a=\frac{28-4b}{8}

Now plug this into the first equation.

9a+3b=30\\9(\frac{28-4b}{8})+3b=30

Distribute the 9

(\frac{252-36b}{8}) +3b=30

Break down the fraction.

\frac{252}{8}-\frac{36b}{8}+3b=30

Simplify.

\frac{63}{2}-\frac{9}{2}b+3b=30

Subtract \frac{63}{2}

-\frac{9}{2}b+3b=30-\frac{63}{2}

Combine like terms.

\frac{-9+2*3}{2}b=\frac{30*2-63}{2}

\frac{-9+6}{2}b=\frac{60-63}{2}

\frac{-3}{2}b=\frac{-3}{2}

Muliply by the reciprocal or inverted fraction next to b.

(-\frac{2}{3})(-\frac{3}{2}) b=-\frac{3}{2}(-\frac{2}{3})

b=1

Now plug this value into any of the equations to find the value of a.

8a+4b=28\\8a+4(1)=28\\8a+4=28\\8a=28-4\\8a=24\\a=\frac{24}{8}\\ a=3

5 0
4 years ago
What is the first step to follow before working on the Power Steering system of a hybrid? A. Disconnect the Battery B. Disable t
OLEGan [10]
The right answer is A :)
5 0
3 years ago
Read 2 more answers
Given TS¯¯¯¯¯¯¯ and TU¯¯¯¯¯¯¯ are midsegments, PR=18.2, TS=6.5. Find QU . A. 9.1 B. 3.25 C. 13 D. 6.5
AleksAgata [21]

Answer:

The correct option is;

D. 6,5

Step-by-step explanation:

TS and TU are midsegments

Segment PR = 18.2

Segment TS = 6.5

Given that TS is the midsegment of PR and PQ, therefore, TS = 1/2×QR

Which gives;

Segment QR = 2×TS = 2 × 6.5 = 13

Segment QR = 13

Given that TU is a midsegment to PQ and QR, we have that QU = UR

Segment QR = QU + UR (segment addition postulate)

Therefore, QR = QU + QU (substitute property of equality)

Which gives;

QR = 2×QU

13 = 2×QU

Segment QU = 13/2 = 6.5

The length of segment QU is 6.5.

5 0
3 years ago
What Values of X Makes these equations true?<br><br> Label Them as <br> 1.<br> 2.
maks197457 [2]

Answer: your answer is answer

Step-by-step explanation; the physics of the calculations say you are not einstien.

4 0
3 years ago
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