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3 years ago

20 wins out of 36 games

Mathematics

1 answer:

rusak2 [61]3 years ago

3 0

Answer:

55.56%

Step-by-step explanation:

= (20 / 36) × 100

= 0.56 × 100

= 55.56%

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Find the indicated quantities for y equals f (x )equals 3 x squared. (A) Simplify StartFraction f (3 plus Upper Delta x )minus

torisob [31]

Answer:

Step-by-step explanation:

Given that a function f(x) is given as

$y=f(x) = 3x^2$

A) $f(x+ \Delta x) = 3((x+ \Delta x)^2=3(x^2+2x \Delta x+\Delta x^2)\\f(x) = 3x^2\\f(x+ \Delta x) -f(x) = 6x \Delta x +\Delta x^2$

Now divide by delta x

$\frac{f(x+ \Delta x) -f(x)}{\Delta x}\\=6x+\Delta x$

B) When delta x tends to 0, this becomes

$6x$

(NOte: This is the derivative of f(x))

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3 years ago

A geometric sequence has an initial value of 9 and a common ratio of 5. What function could represent this situation?

leonid [27]

Answer:

The functions that represent this situation are A and C.

Step-by-step explanation:

A geometric sequence goes from one term to the next by always multiplying or dividing by the same value.

In geometric sequences, the ratio between consecutive terms is always the same. We call that ratio the common ratio.

This is the explicit formula for the geometric sequence whose first term is k and common ratio is r

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3 years ago

PLEASE HELP I WILL GIVE YOU A BRAINLIEST! During a basketball game, Tom attempted 25 shots and made 9. He says he made 40% of th

postnew [5]

Answer:

Correct I think

Step-by-step explanation:

9 is nearly half of 25. (12.5) Half is equal to 50%. 40 is close to 50 and 9 is close to 12.5. So, he is correct. I think, hope this helps.

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3 years ago

Needdd hellpppppssssssss

Ratling [72]

Answer:

Choice number one:

$\displaystyle \frac{5}{10}\cdot \frac{4}{9}$ .

Step-by-step explanation:

Let $A$ be the event that the number on the first card is even.
Let $B$ be the event that the number on the second card is even.

The question is asking for the possibility that event $A$ and $B$ happen at the same time. However, whether $A$ occurs or not will influence the probability of $B$ . In other words, $A$ and $B$ are not independent. The probability that both $A$ and $B$ occur needs to be found as the product of

the probability that event $A$ occurs, and
the probability that event $B$ occurs given that event $A$ occurs.

5 out of the ten numbers are even. The probability that event $A$ occurs is:

$\displaystyle P(A) = \frac{5}{10}$ .

In case A occurs, there will only be four cards with even numbers out of the nine cards that are still in the bag. The conditional probability of getting a second card with an even number on it, given that the first card is even, will be:

$\displaystyle P(B|A) = \frac{4}{9}$ .

The probability that both $A$ and $B$ occurs will be:

$\displaystyle P(A \cap B) = P(B\cap A) = P(A) \cdot P(B|A) = \frac{5}{10}\cdot \frac{4}{9}$ .

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3 years ago

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