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AlexFokin [52]
3 years ago
8

The middle school is 2.72 Kilometers from Kim's house and 1.54 kilometers from Terri's house. How much farther in meter does Kim

live from the middle school than Terri
Mathematics
1 answer:
TiliK225 [7]3 years ago
4 0

Answer: 1,180  meters.

Step-by-step explanation:

Hi, to answer this question we have to subtract Terri's distance from the school (1.54) to Kim's distance from the school (2.72)

Mathematically speaking:

2.72 km - 1.54km = 1.18 km

Since the answer must be expressed in meters.

1000 meters = 1 kilometer

1.18 km x 1000 m/km = 1,180 meters.

Feel free to ask for more if needed or if you did not understand something.

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Solve for h.<br> 15.3 + 1 h =1.3- 1 h
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Answer:

-7 = h

Step-by-step explanation:

15.3 + 1h = 1.3 - 1h

<u>         +1h          +1h</u>

15.3 + 2h = 1.3

Remember what you do to one side you MUST do to the other.

 15.3 + 2h = 1.3

<u>-15.3           -15.3</u>

2h = -14

Now to isolate the variable you divide both sides by 2 to get, h = -7

Hope that helps and have a great day!

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What is 363 rounded to the nearest ten
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I think the answer is 360
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Thomas needs at least 8 apples to make an apple pie. He has 3 apples. If x represents the number of apples Thomas still needs, w
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Answer:

x + 3 greater than or equal to 8 would be the solution

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If (x, 3.4) is a solution to the equation 3x – 5y = 55, what is the approximate value of x?
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A pool measuring 10 meters by 26 meters is surrounded by a path of uniform​ width, as shown in the figure. If the area of the po
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Based on the measurements of the pool and the path of uniform width, the area of the width and length of the path can be found to be 28.8 meters.

<h3>How to find the width and length?</h3>

First, find the area of the pool:

= Length x Width

= 10 x 26

= 260 meters ²

The area of the path can therefore be found to be:

= Total area of pool and path combined - Area of pool

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Seeing as the path has uniform width, that means that the width is the same and the length so the width and length of the pool is:
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In conclusion, the width and length of the path are 28.8 meters.

Find out more on combined area at brainly.com/question/12966430

#SPJ1

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