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mr Goodwill [35]

3 years ago

5

A helicopter is 105 ft. above sea level, while a submarine is directly underneath the helicopter and has a position of 62 ft. be

low sea level. Which expression will correctly calculate the distance between the helicopter and the submarine?

1 answer:

chubhunter [2.5K]3 years ago

4 0

167 feet is the difference between positions

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Pre college need help

NARA [144]

Answer:

C

Step-by-step explanation:

5 0

3 years ago

How do I answer this question

Gnom [1K]

First you have to make it multiplication so you flip 5/2 around and the two “2’s” will cancel each other so it will be 17/5 or 3 2/5

6 0

3 years ago

Which expression is equivalent to

Nat2105 [25]

Answer : The correct option is $\frac{1}{36a^{4}b^{10}}$

Step-by-step explanation :

According to the BODMAS rule, when the expression contains brackets open ((), {}, []) we have to first simplify the bracket followed by of (powers and roots etc.) and then we have to solve the division, multiplication, addition and subtraction from left to right order (respectively).

The given expression is:

$[\frac{(2a^{-3}b^4)^2}{(3a^5b)^{-2}}]^{-1}$

$=[\frac{(3a^5b)^{-2}}{(2a^{-3}b^4)^2}]^{1}$

$=[\frac{1}{(3a^5b)^{2}}\times \frac{1}{(2a^{-3}b^4)^2}]$

$=[\frac{1}{9a^{10}b^2}\times \frac{1}{4a^{-6}b^8}]$

$=[\frac{1}{9a^{10}b^2}\times \frac{a^6}{4b^8}]$

$=\frac{1}{36a^{4}b^{10}}$

Thus, the given expression is equivalent to $\frac{1}{36a^{4}b^{10}}$

5 0

4 years ago

If a coin is flipped five times and a head comes up two times, what is the relative frequency of head coming up? A) 0.40 B) 0.20

Anton [14]

Answer:

A) 0.40

Step-by-step explanation:

5 goes into 100, 20 times. Each coin flip is equal to 0.20, so 2 heads would be 0.40.

4 0

4 years ago

What is 9 + t/12 = -3

klemol [59]

9 + t/12 = -3

t/12 = -12

t = -144

hope this helps

3 0

3 years ago

Read 2 more answers