THIS IS THE COMPLETE QUESTION BELOW;
The weekly salaries of sociologists in the United States are normally distributed and have a known population standard deviation of 425 dollars and an unknown population mean. A random sample of 22 sociologists is taken and gives a sample mean of 1520 dollars.
Find the margin of error for the confidence interval for the population mean with a 98% confidence level.
z0.10 z0.05 z0.025 z0.01 z0.005
1.282 1.645 1.960 2.326 2.576
You may use a calculator or the common z values above. Round the final answer to two decimal places.
Answer
Margin error =210.8
Given:
standard deviation of 425
sample mean x=1520 dollars.
random sample n= 22
From the question We need to to calculate the margin of error for the confidence interval for the population mean .
CHECK THE ATTACHMENT FOR DETAILED EXPLANATION
Answer:184ft²
Step-by-step explanation:2(5×10)+2(4×6/2)+(6×10)
100+24+60=184
PLEASE MARK ME AS BRAINLIEST!!!
<em><u>Answer:</u></em>
The answer is 70 degrees.
<em><u>Step-by-step explanation:</u></em>
1. All the angles in a circle add up to 360, and the red square thing in the TVU angle means it's a 90 degree angle.
2. Add 150 plus 50 plus 90 = 290
3. 360 degrees (total) - 290 degrees = 70 degrees! :)
Answer:
need points sorry 38484343
Step-by-step explanation:
well the quotient means the answer to a division, so in this case:
18 ÷ 1000 = 0.018