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Luda [366]
2 years ago
11

What is the internal angle sum of a quadrilateral? (Hint: A quadirlateral has 4 sides.) OA) 90 OB) 180 OC) 360 OD 540

Mathematics
2 answers:
shtirl [24]2 years ago
5 0

The internal angle sum of a quadrilateral is :

C. 360°

The sum of internal angles of a polygon is determined by a formula :

\longmapsto (n - 2) × 180°

where n represents number of sides.

In a quadrilateral there are four sides,

So, plugging 4 in the formula :

  • (4 - 2) \times 180°

  • 2 \times 180°

  • 360°

_____________________________

\mathrm{ \#TeeNForeveR}

andrezito [222]2 years ago
3 0

Answer:

C. 360

Step-by-step explanation:

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Maslowich
<h3><u>Given Information :</u></h3>

  • Length of parallel sides = 60 ft and 40 ft
  • Height of the trapezoid = 30 ft

<h3><u>To calculate :</u></h3>

  • Area of the trapezoid.

<h3><u>Calculation :</u></h3>

As we know that,

\bigstar \: \boxed{\sf {Area_{(Trapezium)} = \dfrac{1}{2} \times ( a + b) \times h}} \\

  • a and b are length of parallel sides.
  • h denotes height.

<em>S</em><em>u</em><em>b</em><em>s</em><em>t</em><em>i</em><em>t</em><em>u</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>valu</em><em>es</em><em>,</em><em> </em><em>we</em><em> </em><em>get</em><em> </em>:

\longmapsto Area = \sf \dfrac{1}{2} × ( 60 + 40 ) × 30 ft\sf ^2

\longmapsto Area = \sf \dfrac{1}{2} × 100 × 30 ft\sf ^2

\longmapsto Area = 1 × 100 × 15 ft\sf ^2

\longmapsto Area = 100 × 15 ft\sf ^2

\longmapsto <u>Area = 1500 ft</u>\sf ^2

Therefore,

  • Area of the trapezoid is <u>1500 ft\sf ^2</u>

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Sum or products of 4x47
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What Is the answer to 10ac-x/11=-3
cestrela7 [59]
  1. Multiplty both sides by 11. 11 times 11 cancels out, 11 times -3 equals -33. You should get 10ac - x = -33
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revised tada!

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Answer:

85.71

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