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3 years ago

What is the equation of the line that passes through the point (-4, -6) and has a slope of -1/2?

Mathematics

2 answers:

Ede4ka [16]3 years ago

5 0

Answer:

y=-1/2x - 8

Use desmos to help with these problems

Vikentia [17]3 years ago

3 0

Answer:

y=(-1/2)x-8

Step-by-step explanation:

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I’ll give the Brainliest to who answers this question with a reasonable explanation.

topjm [15]

Answer:

$143.8\:\mathrm{ft^2}$

Step-by-step explanation:

The composite figure shown in the picture consists of a semi-circle and a trapezoid. We can even break this trapezoid into a rectangle and two triangles for even simpler calculations. We can find the total area of the figure by simply adding the total area of the shapes we will break the figure into:

Area of semi-circle (half the area of a circle): $\frac{1}{2}\cdot 4.5^2\cdot \pi$

Area of trapezoid (average of bases multiplied by height): $16\cdot 7$

Thus, the total area of the figure is:

$\frac{1}{2}\cdot 4.5^2\cdot \pi+16\cdot 7=143.808625618\approx \boxed{143.8\:\mathrm{ft^2}}$

3 0

3 years ago

Solve 10 3/4 - 6 4/5

MAXImum [283]

Alright, so the first thing I would do is find the LCM of the dividends, which is 20. So we have 10 15/20 and 6 16/20. You can either leave it there and just carry the one (20 in this case) for 3 19/20.
If you multiply 10 by 20 and add 15, or 6 by 20 and add 16 (which I think is easier) you get 215/20 - 136/20 = 79/20. It can be simplified from here if you teacher wants it in the future.

7 0

3 years ago

Read 2 more answers

Which are perfect squares? Check all that apply. 49 17 g 143 225

Vika [28.1K]

<span>49 17 g 143 225
</span><span>
you have g in here
is g is 9?

perfect squares
49 = 7^2
225 = 15^2</span>

5 0

3 years ago

Read 2 more answers

which of the following expresses the coordinates of the foci of the conic section shown below? (x-2)^2/4+(y+5)^2/9

elena55 [62]

Step-by-step explanation:

$\frac{(x - 2) {}^{2} }{4} + \frac{(y + 5) {}^{2} }{9} = 1$

This is the equation of the ellipse. Since the denominator is greater for the y values, we have a vertical ellipse. Remember a>b, so a

The formula for the foci of the vertical ellipse is

(h,k+c) and (h,k-c).

where c is

Our center (h,k) is (2, -5)

${c}^{2} = {a}^{2} - {b}^{2}$

Here a^2 is 9, b^2 is 4.

${c}^{2} = 9 - 4$

${c}^{2} = 5$

$c = \sqrt{5}$

So our foci is

$(2, - 5 + \sqrt{5} )$

and

$(2, - 5 - \sqrt{5} )$

6 0

2 years ago

Greg is trying to solve a puzzle where he has to figure out two numbers, x and y. Three less than two-third of x is greater than

Fittoniya [83]

Inequation 1:

$\frac{2}{3}x-3 \geq y$

to plot the pairs (x, y) for which the inequation holds, draw the line $y=\frac{2}{3}x-3$

then pick a point in either side of the line. If that point is a solution of the inequation, than color that region of the line, if that point is not a solution, then color the other part of the line.

we do the same for the second inequation. Then the solution, is the region of the x-y axes colored in both cases.

inequation 2:

$y+ \frac{2}{3}x\ \textless \ 4$

$y\ \textless \ - \frac{2}{3} x+ 4
$

draw the lines

i) $y=\frac{2}{3}x-3$ use points (0, -3), (3, -1)

ii) $y=- \frac{2}{3} x+ 4$ use points ( 0, 4), (3, 2)

let's use the point P(3, 3) to see what region of the lines need to be coloured:

$\frac{2}{3}x-3 \geq y$ ;
$\frac{2}{3}(3)-3 \geq 3$
$2-3 \geq 3$ , not true so we color the region not containing this point

$y+ \frac{2}{3}x\ \textless \ 4$
$(3)+ \frac{2}{3}(3)\ \textless \ 4$
$3+ 5\ \textless \ 4$ not true, so we color the region not containing the point (3, 3)

The graph representing the system of inequalities is the region colored both red and blue, with the blue line not dashed, and the red line dashed.

4 0

4 years ago