Ask question

Ask question

All categories

3 years ago

11

Mary, Amy, and Kim babysit. Last week, Kim earned 7.50 dollars more than Mary, and Amy earned twice as much as Kim. If Mary earn

ed 12.80 dollars, how much did Amy and Kim earn

2 answers:

AveGali [126]3 years ago

7 0

Answer: Kim has 20.30 Amy has 40.60

Step-by-step explanation:

ANEK [815]3 years ago

4 0

Answer:

Kim earned $20.30 and Amy earned $40.60

Step-by-step explanation:

Im just built different

You might be interested in

Brett has 2 1/2 pounds of bird seed left to share equally among 4 bird cages in his pet shop. How many pounds can he put in each

Ksju [112]

Answer:

Brett can put $\frac{5}{8}$ = 0.625 pounds in each bird cage.

Step-by-step explanation:

The total amount of bird seed left = $2\frac{1}{2}$ pounds

= $\frac{5}{2}$ pounds

Number of birds in pet shop = 4

So, the share of each bird = $\frac{\textrm{Total available seeds}}{\textrm{Total number of birds in the pet shop}}$

= $\frac{\frac{5}{2} }{4} = \frac{5}{2} \times \frac{1}{4} = \frac{5}{8}$

Hence, Brett can put $\frac{5}{8}$ = 0.625 pounds in each bird cage.

6 0

3 years ago

A machine makes 300 boxes in 15 minutes. Which expression equals the unit rate in boxes per minute

sukhopar [10]

Answer:

300*15

Step-by-step explanation:

thats it

7 0

2 years ago

Read 2 more answers

All of the following are rational except<br> Sqrt 0.49<br> Sqrt 19<br> Sqrt 900<br> Sqrt 100

Anna71 [15]

Answer:

0.49

Step-by-step explanation:

for it to be rational there should not be no decimal nor pi .

3 0

2 years ago

Read 2 more answers

Plz help me answer the whole page

dangina [55]

#2 5.88 #3 6.510 #4 7.578 #5 9.835 #6 11.910 #7 3.72

8 0

2 years ago

1. Among 806 people asked which is there favorite seat on a plane, 492 chose the window seat, 8 chose the middle seat, and 306 c

prisoha [69]

Answer:

See explanation

Step-by-step explanation:

Among 806 people asked which is there favorite seat on a plane, 492 chose the window seat, 8 chose the middle seat, and 306 chose the aisle seat, then

$P(\text{Window seat})=\dfrac{492}{806}=\dfrac{246}{403}\\ \\P(\text{Middle seat})=\dfrac{8}{806}=\dfrac{4}{403}\\ \\P(\text{Aisle seat})=\dfrac{306}{806}=\dfrac{153}{403}$

a) One randomly selected person preferes aisle seat with probability

$\dfrac{153}{403}$

b) Two randomly selected people both prefer aisle seat (with replacement) is

$\dfrac{306}{806}\cdot \dfrac{306}{806}=\dfrac{153}{403}\cdot \dfrac{153}{403}=\dfrac{23,409}{162,409}$

c) Two randomly selected people both prefer aisle seat (without replacement) is

$\dfrac{306}{806}\cdot \dfrac{305}{805}=\dfrac{153}{403}\cdot \dfrac{61}{161}=\dfrac{9,333}{64,883}$

8 0

2 years ago