Choose the polygon that is a regular quadrilateral

Mathematics

1 answer:

Sati [7]2 years ago

7 0

"Regular quadrilateral" means it has four sides, and the
sides AND the inside angles are all equal.

-- The one at the upper left is a rhombus. All 4 of its sides
are the same length, and the first time I saw it, I picked it.
But then I remembered that in order to be 'regular', the
inside angles also have to be equal, and in a rhombus,
they're not.

-- The one in the lower right is a square. It has four sides,
they're all equal, and the inside angles are all the same too.
So the square is the only one that does the job for you.

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Answer: 560

Step-by-step explanation:

There are [20, 22, 24, 26, 28]: 5 even integers for each ten numbers.

The 20's set can be written as 5*20 + (2+4 + 6 + 8) = 5*20 + (20) = 120

The 30's can be written: 5*30 + 20 = 170

40's: 5*40+20 = 220

50's: 5*50+20 = 270

60's: 5*60+20 = 320

Each set is incremented by 50

We want the sets for 20, 30, and 40, plus the number 50.

(120+170+220+50) = 560

You can also do this in Excel (attached). Set the first cell to 20, the next cell below equal to the cell above plus 2. Then draw the second cell down until you've reached 50. Then sum the cells to arrive at 560.