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2 years ago

Helpp mee pleaseeeeeeeeee

Mathematics

2 answers:

bagirrra123 [75]2 years ago

5 0

Answer:

6xwidthxlength

Step-by-step explanation:

it’s basic

MaRussiya [10]2 years ago

3 0

Answer:

6 x width x length

Step-by-step explanation:

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HELP LOTS OF POINTS AND BRAINLIEST

Gekata [30.6K]

Answer:

12. P(4) = 1/6

13. P(odd) = 3/6 = 1/2

Step-by-step explanation:

hope this helps, pls mark brainliest :D

7 0

2 years ago

During the football game, Justin caught 3 passes. One was for a touchdown and was a 52 yard gain. The other was for a first down

pogonyaev

Answer:

Step-by-step explanation:

52+17-10=59

5 0

2 years ago

Charles will babysit for up to 4 hours and charges $7 per hour. Write a function in function notation for this situation.

I am Lyosha [343]

Assume Charles charges $7*3=$21 if he babysits for 2,5 hours (that is 2 and a half hours).

That is we are not considering Charles babysitting exactly 1, 2, 3 or 4 hours, but also in between times.

then we can write the following piecewise function to describe the situation:

f is a function from (0, 4] to {$7, $14, $21, $28}

$f(x)=\begin{cases} 
 \$7 & if \enspace \enspace x\leq 1 \\
 \$14 & if \enspace \enspace 1\ \textless \ x\leq 2 \\
 \$21 & if \enspace\enspace 2\ \textless \ x\leq 3 \\
 \$28 & if \enspace\enspace 3\ \textless \ x\leq 4 \
 \end{cases}$

6 0

2 years ago

The measure of angel A is 55° and is complementary to the measure of angle B. If the measure or angle B is X , what is the value

PSYCHO15rus [73]

Answer:

45 or least

Step-by-step explanation:

I'm guessing that the angel is acute

7 0

2 years ago

One more time!

CaHeK987 [17]

Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

$\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\
x = \frac{\sqrt{19} }{2}$

so we conclude that
$q(\frac{\sqrt{19} }{2} ) = 1/4$

therefore

$p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right) \right)$

plug $x=\sqrt{19}/2$ into p( q(x) ) to get answer

$p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left( \frac{\sqrt{19} }{2}\right)^2 }{ \left( \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow$

$\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow -\dfrac{6\sqrt{19} }{361}$

$p(1/4) = -\dfrac{6\sqrt{19} }{361}$

3 0

2 years ago