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3 years ago

If two pounds of meat will serve 5 people how many pounds will be needed to serve 13 people

1 answer:

4 0

The answer is 5.2 pounds of meat. To find this just divide the number of people by what the information you have about servings. 13/5=2.6(number of sets), then you multiply that by how many pounds are in each set. 2.6 sets* 2 pounds per set= 5.2 pounds.
I hope this helped!

You might be interested in

Game stop is having a 35% off sale on all their video games. If a mage is originally $40.00, how much will it be during the sale

Snowcat [4.5K]

Answer:$26.00

Step-by-step explanation:40 x .35 = 14

40-14=26

8 0

3 years ago

What’s the correct answer for this?

ololo11 [35]

As you can see in the picture, this is 6-8-10 right triangle.

One of angles is 90° so you can find others

$\tan( \alpha ) = \frac{opp}{adj}$

8/6 = 4/3

6/8= 3/4

tan-1(4/3) = 36.9 °

tan-1(3/4) = 53.1 °

tan<R= 53.1 °

Hope this helps ^-^

4 0

3 years ago

According to the scale on a map, 1 inch on the map = 12 miles. How many miles are represented by 4 inches on the map?

Juli2301 [7.4K]

Answer:

60 miles

Step-by-step explanation:

So if 1 inch = 12 miles, you need to find 4 inches. There are multiple ways to achieve this. However ratios/proportions might be easiest.

if 1/12 = 4/x, x is the value of miles. Cross multiply so you get this:

1 4

- = - = 60 = x

12 x

If x equals 60, that means that 4 inches equals 60 miles on the map.

You could also just find an equal fraction by multiplying the top and bottom both by 4.

6 0

3 years ago

If six angles of a heptagon have measures of 122, 153, 168, 105, 162, and 87, what is the measure of the seventh angle?

xxTIMURxx [149]

Answer:

he seventh angles measure is 103

Step-by-step explanation:

Interior angles = (number of side in the polygon - 2) times 180.

So Heptagon interior angles = (7-2)(180) = 900

To find the missing angles add all the given angles together (122, 153, 168, 105, 162, and 87) = 797.

Now The measure of the seventh angles = total angles measure - the six given angles,

The seventh angles measure is 103

900 - 797 = 103

7 0

3 years ago

For what value of k will the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent?

konstantin123 [22]

Answer:

After solve the equations we get value of k=3

Step-by-step explanation:

We need to find value of k for which the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent.

If the lines are concurrent, they pass through same point.

Let:

$x+2y=0--eq(1)\\ 3x-4y-10=0--eq(2)\\ 5x+ky-7=0--eq(3)$

First solving equation 1 and 2 to find values of x and y

From eq(1) we find value of x and put it in eq(2)

$From \ eq(1) x+2y=0\\x=-2y\\Put x=-2y \ in \ eq(2)\\3x-4y-10=0\\3(-2y)-4y-10=0 \\-6y-4y=10\\-10y=10\\y=\frac{10}{-10}\\y=-1$

After solving we get value of y=-1

Now putting in eq(1) to get value of x

$x+2y=0\\x+2(-1)=0\\x-2=0\\x=2$

So, Value of x= 2

Now put value of x=2 and y=-1 into eq(3) to find value of k

$5x+ky-7=0\\5(2)+k(-1)-7=0\\10-k-7=0\\-k+3=0\\-k=-3\\k=3$

So, After solve the equations we get value of k=3

4 0

3 years ago