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3 years ago

11

Ms.beatly Is trying to get healthy and starts running in the morning.She is able to run 5 miles in 45 minutes how many how many

minutes does is for her to run 1 miles

1 answer:

ElenaW [278]3 years ago

6 0

Answer:

1. 9 minutes

Step-by-step explanation:

1. If she runs 5 miles in 45 minutes, you have 5 miles = 45 minutes. If you divide both sides of this ratio by 5, you get 1 miles = 9 minutes

2. Find out how many each person sells per week:

Emily: 4 boxes = 2 weeks

divide both sides by 2

2 boxes = 1 week

Jose: 9 boxes = 3 weeks

divide both sides by 3

3 boxes = 1 week

This means that jose sells more, because 3 boxes > 2 boxes

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Convert 4.824 meters per second to kilometers per hour

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2 years ago

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GarryVolchara [31]

Answer:

Its 16 i will :D

Step-by-step explanation:

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2 years ago

A quadratic function that has the vertex (-2, -4) and passes through the point (-1, -6)

spayn [35]

Answer:

f(x) = -2 (x + 2)² - 4

Step-by-step explanation:

f(x) = a (x - h)² + k (h , k) is vertex h = -2 k = -4

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3 years ago

Find the perimeter of the figure shown to the right.

tia_tia [17]

Step-by-step explanation:

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and that clearly means to just add all side lengths.

that's it.

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2 years ago

Marine biologists have determined that when a shark detectsthe presence of blood in the water, it will swim in the directionin w

siniylev [52]

Solution :

a). The level curves of the function :

$C(x,y) = e^{-(x^2+2y^2)/10^4}$

are actually the curves

$e^{-(x^2+2y^2)/10^4}=k$

where k is a positive constant.

The equation is equivalent to

$x^2+2y^2=K$

$\Rightarrow \frac{x^2}{(\sqrt K)^2}+\frac{y^2}{(\sqrt {K/2})^2}=1, \text{ where}\ K = -10^4 \ln k$

which is a family of ellipses.

We sketch the level curves for K =1,2,3 and 4.

If the shark always swim in the direction of maximum increase of blood concentration, its direction at any point would coincide with the gradient vector.

Then we know the shark's path is perpendicular to the level curves it intersects.

b). We have :

$\triangledown C= \frac{\partial C}{\partial x}i+\frac{\partial C}{\partial y}j$

$\Rightarrow \triangledown C =-\frac{2}{10^4}e^{-(x^2+2y^2)/10^4}(xi+2yj),$ and

$\triangledown C$ points in the direction of most rapid increase in concentration, which means $\triangledown C$ is tangent to the most rapid increase curve.

$r(t)=x(t)i+y(t)j$ is a parametrization of the most $\text{rapid increase curve}$ , then

$\frac{dx}{dt}=\frac{dx}{dt}i+\frac{dy}{dt}j$ is a tangent to the curve.

So then we have that $\frac{dr}{dt}=\lambda \triangledown C$

$\Rightarrow \frac{dx}{dt}=-\frac{2\lambda x}{10^4}e^{-(x^2+2y^2)/10^4}, \frac{dy}{dt}=-\frac{4\lambda y}{10^4}e^{-(x^2+2y^2)/10^4}$

∴ $\frac{dy}{dx}=\frac{dy/dt}{dx/dt}=\frac{2y}{x}$

Using separation of variables,

$\frac{dy}{y}=2\frac{dx}{x}$

$\int\frac{dy}{y}=2\int \frac{dx}{x}$

$\ln y=2 \ln x$

⇒ y = kx^2 for some constant k

but we know that $y(x_0)=y_0$

$\Rightarrow kx_0^2=y_0$

$\Rightarrow k =\frac{y_0}{x_0^2}$

∴ The path of the shark will follow is along the parabola

$y=\frac{y_0}{x_0^2}x^2$

$y=y_0\left(\frac{x}{x_0}\right)^2$

7 0

2 years ago