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Nookie1986 [14]
3 years ago
5

Where do I find something like this? ​

Mathematics
1 answer:
Gnesinka [82]3 years ago
6 0

Answer:

something like what? what do you mean?

Step-by-step explanation:

You might be interested in
9. what is the measure of QSR
Scilla [17]
<h3>Answer:  C) 142 degrees</h3>

=======================================================

Explanation:

Extend segment MN such that it intersects side ST. Mark the intersection as point A. See the diagram below.

We're given that angle MNT is 72 degrees. The angle TNA is equal to 180-(angle MNT) = 180 - 72 = 108 degrees, since angles MNT and TNA add to 180.

For now, focus entirely on triangle TNA. We see from the diagram that T = 34 and we just found that N = 108. Let's find angle A

A+N+T = 180

A+108+34 = 180

A+142 = 180

A = 180-142

A = 38

So angle NAT is 38 degrees.

----------------------------

Since segment MA is an extension of MN, and because MN || SQ, this means MA is also parallel to SQ.

We found at the conclusion of the last section that angle NAT was 38 degrees. Angles QST and NAT are corresponding angles. They are congruent since MA || SQ. This makes angle QST to also be 38 degrees

----------------------------

The angles QSR and QST are a linear pair, so they are supplementary

(angle QSR) + (angle QST) = 180

angle QSR = 180 - (angle QST)

angle QSR = 180 - 38

angle QSR = 142 degrees

5 0
3 years ago
A graph has quantity on the x-axis and price on the y-axis. A supply line goes through (10, 25), (20, 30), (30, 35), (40, 40).A
alexgriva [62]

Answer:

B

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Can someone help me with these kind of fractions<br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20of%20%5Cfrac%7B2%
elena-s [515]

Answer:

   \frac{2}{6} or \frac{1}{3}

Step-by-step explanation:

To find a fraction of a fraction simply multiply the numerators and denominators into another fraction:

\frac{1}{2}*\frac{2}{3} = \frac{2}{6} = \frac{1}{3}

4 0
2 years ago
Read 2 more answers
If PQ=21 cm and QR=5cm, then what are the possible lengths for PR so that line PQ, line QR, and line PR can form a triangle? exp
Klio2033 [76]
We know that PQ is 21 cm and QR is 5 cm. There are only 2 possible answer for this and you use only one formula. It's called the Pythagorean theorem. 

The first possible is this. If the hypotenuse(the longest side of a triangle) is PR, we do:
 a² + b² = c² ←Fill in the numbers
21² + 5² = c²
441 + 25 = c²
466 = c²
√466 = 21.12 cm←Possible length

The second possible is this:
5² + b² = 21²
25 + b² = 441
b² = 441 - 25
b² = 416
√416 = 20.4←Another possible answer
8 0
4 years ago
If you're good at trig please help meeeee<br> Show full working out ;)
Trava [24]

We break down the area into two triangles - since we're given all their side lengths, we use Heron's formula: [area]=\sqrt{s(s-a)(s-b)(s-c)}, where s=\frac{a+b+c}{2}

[ABD]=\sqrt{(265)(115)(85)(65)}\approx 12975.92

[CBD]=\sqrt{(225)(125)(75)(25)}\approx 7261.84

[ABCD]=[ABD]+[CBD]\approx\boxed{20238\,\text{m}^2}.

7 0
3 years ago
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