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3 years ago

Someone Help? Im confuzzled

Mathematics

1 answer:

cupoosta [38]3 years ago

3 0

Answer: 16π

Step-by-step explanation:

First, solve for total area:

A = πr^2

A = π(8^2) = 64π

Then, find 1/4 of the area of the whole (since this is only a quarter circle)

A/4 = (64π)/4 = 16π

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After earning interest, the balance of an account is $420. The new balance is 7/6bof the original balance. Write an equation tha

puteri [66]

Well, we know that the total amount is $420, so we can already set one side of the equation. =420. Also, it said that the $420 is (equal to) 7/6b (b for balance).
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4 years ago

Match each letter listed to the correct family of elements.

tekilochka [14]

The answers are

D --> Boron family

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3 years ago

a game room has a floor that is 120 feet by 75 feet. a scale drawing of the floor on grid paper uses a scale of 1 unit: 5 feet.

GarryVolchara [31]

Answer:

The dimensions of the scale drawing are 24ft by 15ft.

Step-by-step explanation:

First divide 120 by 5 which equals. Then divide 75 by 5 and get the answer 15. I hope this helps you out! -belle

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4 years ago

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Timber beams are widely used in home construction. When the load (measured in pounds) per unit length has a constant value ove

Delicious77 [7]

Answer:

a) 0.4

b) 0.133

c) $L \geq 99$

Step-by-step explanation:

We are given the following information in the question:

The load is said to be uniformly distributed over that part of the beam between 90 and 105 pounds per linear foot.

a = 90 and b = 105

Thus, the probability distribution function is given by

$f(x) = \displaystyle\frac{1}{b-a} = \frac{1}{105-90} = \frac{1}{15},\\\\90 \leq x \leq 105$

a) P( beam load exceeds 99 pounds per linear foot)

P( x > 99)

$=\displaystyle\int_{99}^{105} f(x) dx\\\\=\displaystyle\int_{99}^{105} \frac{1}{15} dx\\\\=\frac{1}{15}[x]_{99}^{105} = \frac{1}{15}(105-99) = 0.4$

b) P( beam load less than 92 pounds per linear foot)

P( x < 92)

$=\displaystyle\int_{90}^{92} f(x) dx\\\\=\displaystyle\int_{90}^{92} \frac{1}{15} dx\\\\=\frac{1}{15}[x]_{90}^{92} = \frac{1}{15}(92-90) = 0.133$

c) We have to find L such that

$\displaystyle\int_{L}^{105} f(x) dx\\\\=\displaystyle\int_{L}^{105} \frac{1}{15} dx\\\\=\frac{1}{15}[x]_{L}^{105} = \frac{1}{15}(105-L) = 0.4\\\\\Rightarrow L = 99$

The beam load should be greater than or equal to 99 such that the probability that the beam load exceeds L is 0.4.

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4 years ago

Chin was shown the graph of a line that contained point (1, 7). He wrote f(x) = 4x + 3 to correctly represent the line. Which of

natita [175]

Answer: C

Step-by-step explanation: Edgenuity

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3 years ago

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