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3 years ago

PLEASE ANSWER ASAP. THANK YOU!!

Mathematics

2 answers:

shtirl [24]3 years ago

8 0

Answer: Add the areas of two half circles and a trapezoid.

Step-by-step explanation:

algol [13]3 years ago

3 0

Answer:

D: Add the areas of a trapezoid and two half circles.

Step-by-step explanation:

This one is wrong as the figure contains 2 triangles and a rectangle also if proper divisions are drawn. Hence, rest options are true except option D. Option D is incomplete.

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Pls answer number 5 evaluate each expression for the giving values of the variables

trasher [3.6K]

Answer:

where the expression?

Step-by-step explanation:

so I can help u out?

8 0

3 years ago

A quadrilateral has three angles that measure 90 100 and 120 which is the measurement of the fourth angle

Lesechka [4]

Answer:

The final angle is 50

Step-by-step explanation:

All quadrilaterals have interior angles that add up to 360. So we can subtract these numbers from 360 to get the final angle.

360 - 90 - 100 - 120 = 50

6 0

4 years ago

Consider a pipe of length 80.0 cm open at both ends. what is the lowest frequency f of the sound wave produced when you blow int

SOVA2 [1]

To answer the problem we would be using the formula:v=λ*f
where v=343 m/s
length of standing wave
λ=2*L=1.6m (since both of the ends are open),
L=80.0cm =0.8m; but we are going to rearrange it.
Therefore fundamental frequency is:
f=v/λ
= 343/(2*0.8)
=214.375 Hz

5 0

3 years ago

Solve the formula for the specified variable. d = bx for b

Anit [1.1K]

Answer:

d/x

Step-by-step explanation:

$d=bx\\\frac{d}{x} =b$

7 0

3 years ago

Show that the function has at least one zero between x=1 and x=2

ANTONII [103]

Answer:

See Below.

Step-by-step explanation:

We are given the function:

$\displaystyle f(x) = 7x^5-9x^4-x^2$

And we want to show that it has at least one zero between x = 1 and x = 2.

Because the function is a polynomial, it is everywhere continuous.

Evaluate the function at x = 1 and x = 2:

$\displaystyle \begin{aligned} f(1) & = 7(1)^5 - 9(1)^4 - (1)^2 \\ \\ & = -3\end{aligned}$

And:

$\displaystyle \begin{aligned} f(2) & = 7(2)^5 - 9(2)^4 - (2)^2 \\ \\ & = 76 \end{aligned}$

Therefore, because the function changes signs from x = 1 to x = 2 and is continuous on the interval [1, 2], by the intermediate value theorem, there must exist at least one zero in the interval.

7 0

2 years ago