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kotykmax [81]
3 years ago
7

What is log7 1 equal to

Mathematics
1 answer:
igomit [66]3 years ago
3 0

Answer:

1.85

Step-by-step explanation:hope this helps god bless

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Determine whether it is possible to form a triangle using each set of segments with the given measurements.
Gnesinka [82]
Are we talking about edges or the physical sides of the triangle?

If edges (corners / angles of the triangle), then no, because it doesn’t add up to 180. I don’t think the measurements of the sides matter, tho.
8 0
2 years ago
Can you help me im not that good at math and its a clear photo<br><br> y =___x^2+__x+______
geniusboy [140]
  • Vertex/General Form: y = a(x - h)^2 + k, with (h,k) as the vertex
  • (x + y)^2 = x^2 + 2xy + y^2
  • Standard Form: y = ax^2 + bx + c

So before I put the equation into standard form, I'm first going to be putting it into vertex form. Since the vertex appears to be (-1,7), plug that into the vertex form formula:

y=a(x-(-1))^2+7\\y=a(x+1)^2+7

Next, we need to solve for a. Looking at this graph, another point that is in this line is the y-intercept (0,5). Plug (0,5) into the x and y placeholders and solve for a as such:

5=a(0+1)^2+7\\5=a(1)^2+7\\5=a+7\\-2=a

Now we know that <u>our vertex form equation is y = -2(x + 1)^2 + 7.</u>

However, we need to convert this into standard form still, and we can do it as such:

Firstly, solve the exponent: y = -2(x^2+2x+1) + 7

Next, foil -2(x^2+2x+1): y = -2x^2-4x-2+7

Next, combine like terms and <u>your final answer will be: y = -2x^2-4x+5</u>

3 0
3 years ago
I NEED ANSWER ASAP!!!! AND PLEASE GIVE ANSWER ACCORDING TO THE GRAPH BELOW :)))
podryga [215]

Answer:

ok so put one point on (0, 1) and another on (3, -3)

brainliest pls :)

5 0
2 years ago
What’s the correct answer for this?
Sladkaya [172]

(0,3)

Please see the photo I added, if you do not understand, specify in the comments

3 0
3 years ago
What is the quotient in simplest form?
aliina [53]

Answer:4/7

Step-by-step explanation: cross-canceling helps

12/7×1/3

4/7×1/1=4/7

7 0
3 years ago
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