Answer: (a) There is a clear outlier in the data.
Step-by-step explanation:
The statement relates that sample= 24
Confidence interval= 80.2 to 89.8.
Now the data does not mention anywhere the standard deviation which is an important parameter in using the t-procedure rather we assume that standard deviation is not known. So, the most worrying part is the skewness and the presence of strong outliers in the t-procedure.
So, the option a) is correct meaning a clear outlier in the data.
The number is 79 that is prime
4x + 2y = 8 (1)
8x + 4y = -4y (2)
A) Two lines are parallel if they have the same gradient
- putting both equations into the gradient- intercept form ( y = mx + c where m is the gradient)
(1) 4x + 2y = 8
2y = 8 - 4x
y = -2x + 4
(2) 8x + 4y = -4y
<span> </span>8x = -4y - 4y
y =

y = -x
<span>
Thus the gradient of the two equations are different and as such the two lines are not parallel</span>
B) When two lines are perpendicular, the product of their gradient is -1

p = (-2) * (-1)
p = 2
<span> ∴
the two lines are not perpendicular either.</span>
Thus these lines are SKEWED LINES
Answer:
11 i think
Step-by-step explanation:
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