5:7, 15:21. Hope this helps!!!
I know the answer when you find your answer contact me and we will compare answers.
So car A travels Distance = 60 km/hr*(1+x)
Car B travels Distance = 75 km/hr(x)
Where x is the time in hours.
Those two equations are equal when on overtakes the other
so:
60 +60x = 75x
60=15x
x=4, but my expression is written to count from when car B commenced travel. So total time is 5 hours from the car A setting off.
Answer:
A. {16}
Step-by-step explanation:
1/4 = x^-1/2
We have the exponent rule a^-1 = 1/a^1
Applying the rule, we get
1/4 = 1/x^1/2
x^1/2 = √x
1/4 = 1/√x
Now let's cross multiplying, we get
√x = 4
Taking square on both sides, we get
x = 16
The answer: A. {16}
Hope this will helpful.
Thank you.
Answer:
5.5296
Step-by-step explanation:
to evaluate the expression 4x^4 y^3 we would substitute the value of x and y into it and evaluate. since x = 1/5 and y = 6
4x^4 y^3
4 × x^4 × 4× y³
4 × (1/5)∧4 × 4 × 6³
4× (0.2)∧4 × 4 × 216
4 × 0.0016 × 864
0.0064 × 864
5.5296
