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Jobisdone [24]
3 years ago
12

Kalino earned 85, 95, 93, and 80 points on the 4 tests, each worth 100 points, given so far this term. How many points must he e

arn on his fifth test, also worth 100 points, to average 90 points for the 5 tests given this term?
Mathematics
2 answers:
Anit [1.1K]3 years ago
6 0

Answer:

Kalino would need to earn at least a 97 on his fifth test.

Step-by-step explanation:

The average is calculated by adding up the amounts earned on each test and dividing by the total number of tests.  In this case, the score for the last test is not known, but the expected average of 90 points is, so we can set up an equation to solve for the unknown test value:

\frac{85+95+93+80+x}{5} =90

'x' represents the score of the fifth test.  Using inverse (opposite) operations and doing the same operation to both sides of the equation, we can first multiply both sides by 5:

\frac{353+x}{5} x 5 = 90 x 5

353 + x = 450, now subtract 353 from both sides: 353 -353 + x = 450 - 353

x = 97

Inga [223]3 years ago
6 0

Answer:

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hope this helps : )

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The simplification of the polynomial expression will give 3x² - 20x + 8.

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The polynomial expression is given as:

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3 0
2 years ago
Solve 5r2 – 12 = 68. {±4} {±5} {±3} {±6}
sashaice [31]

Hey there!

Assuming you meant

5r^2 - 12 = 68

If so, follow these steps so it can be a little bit easier to solve

Firstly, we have to add by 12 on each of your sides

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5r^2 = 5r^2 \\ \\ 68 + 12 = 80

We get: 5r^2 =80

Now, we have divide by 5 on each of your sides

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Therefore , your answer is:r = ±4

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

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