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KIM [24]
3 years ago
14

Help please will mark brainliest

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
8 0

Answer:

1.) 20z^5

2.) 8m^5 · 6p^7 · 3mp^0

Step-by-step explanation:

4z^3 · z^2 · 5z

first, multiply 4z · 1z = 4z and add the exponents 3 + 2 = 5

4z^5 · 5z

multiply 4z · 5z and keep the exponents

20z^5

2m^3p^4 · 4m^2p^3 · 3mp^0

find just the "m" variables: 2m^3 · 4m^2 and same as before multiply then add the exponents = 8m^5

now do the same for the "p" variables: 3p^4 · 2p^3 = 6p^7

and for the "mp" variable: 3mp^0

put it all together and this is the simplest form because we don;t know the values of the variables:

8m^5 · 6p^7 · 3mp^0

Hope this helps! If you have any additional questions please don't hesitate to ask me or your teacher to be sure you master the subject. :) Stay safe and please mark brainliest!

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Help!!!! ASAP!!!!!!!!
Kay [80]

Answer:-14x-9y=6

Step-by-step explanation:

-7x-y=0

7x+8y=-6

--------------

-14x-9y=6

5 0
3 years ago
Which of the following functions shown in the table below is not an exponential function?
kramer

Answer:

B. f(x)

D. h(x)

Step-by-step explanation:

An exponential function will have a common ratio.

We check and see if the consecutive terms has a common ratio.

For f(x),

\frac{5}{2}  \ne \frac{10}{5}

This is not an exponential sequence.

For g(x), we have:

\frac{2}{1}  =  \frac{4}{2}  =  \frac{8}{4}  = 2

For h(x),

\frac{1.25}{1}  \ne \frac{1.5}{1.25}

This is not an exponential sequence

For k(x),

\frac{16}{64}  =  \frac{4}{16}  =  \frac{1}{4}  =  \frac{0.25}{1}

6 0
4 years ago
How do you use the law of cosines or law of sines if you are given a=13 m, b=8.5 m, and c=9 m?
Rus_ich [418]
The law of cosines is 
c= square root of a^2 + b^2 - 2ab cos c

the law of sines is
a = b(sin a /sin b)
3 0
3 years ago
A man rides a bicycle a distance of 48 miles in a certain amount of time. If the man increased his speed by 2 miles per hour, he
seropon [69]
Recall your d = rt, distance = rate * time.

so, in his usual speed, say is hmm "r" mph, so in his usual "r" speed, he rolls on for the 48 miles and it takes him "t" hours to get there.

now, if he increases his speed by 2 mph, then his new speed is "r + 2", and he arrives there 4 hours earlier, so if he took "t" hours going at "r" speed, then when he's going faster at "r + 2", he only takes "t - 4" hours, for the same 48 miles.

\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
\textit{usual speed}&48&r&t\\
\textit{faster speed}&48&r+2&t-4
\end{array}
\\\\\\
\begin{cases}
48=rt\implies \frac{48}{r}=\boxed{t}\\
48=(r+2)(t-4)\\
----------\\
48=(r+2)\left( \boxed{\frac{48}{r}}-4 \right)
\end{cases}
\\\\\\
48=(r+2)\left( \cfrac{48-4r}{r} \right)\implies 48r=(r+2)(48-4r)


\bf 48r=48r-4r^2+96-8r\implies 0=-4r^2+96-8r
\\\\\\
4r^2+8r-96=0\implies r^2+2r-24=0
\\\\\\
(r+6)(r-4)=0\implies r=
\begin{cases}
-6\\
\boxed{4}
\end{cases}

it cannot be a negative value, since is just a forward speed rate, so can't be -6.
8 0
3 years ago
Read 2 more answers
Please help! Show your work Please! I’ll give Brainliest and more! I need this for tomorrow!
OverLord2011 [107]

Answer:

22-25

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
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