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Kitty [74]
4 years ago
8

6) mcPOF x + 42, mCPOR - 87°,and mzFOR r + 65. Find x.

Mathematics
1 answer:
Stels [109]4 years ago
6 0
Answer:  x =  -10 .
_________________________________________________
Explanation:
_________________________________________________
         x + 42 + x + 65  = 87 ;  Solve for "x" ; 

           2x + 107 = 87 .
 
Subtract "107" from each side of the equation:

           2x + 107 − 107 = 87 <span>− 107 ;

             2x = -20 ;

Divide each side of the equation by "2" ; to isolate "x" on one side of the equation; and to solve for "x" ;
____________________________________
             2x / 2  =  -20/2 ;

                 x = -10 .
______________________________________________</span>
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3 years ago
How to find two consecutive numbers whose squares differ by 15?
LUCKY_DIMON [66]
Let x is the first no. then the other no. will obviously be (x+1)

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4 0
3 years ago
Find the solution set of the following quadratic equations using the quadratic formula.
oksian1 [2.3K]

Answer:

<h3>                1)  x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2</h3><h3>                2)   x_1=-\dfrac13\,,\quad x_2=-3    </h3>

Step-by-step explanation:

<h3>1)</h3>

x^2 - 7x + 9 = 0\quad\implies\quad a=1\,,\ b = -7\,,\ c=9\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot1\cdot9}}{2\cdot1}=\dfrac{7\pm\sqrt{49-36}}2\\\\x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2

<h3>2)</h3><h3>3x^2 + 10x=-3\\\\3x^2+10x+3=0\quad\implies\quad a=3\,,\ b =10\,,\ c=3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-10\pm\sqrt{10^2-4\cdot3\cdot3}}{2\cdot3}= \dfrac{-10\pm\sqrt{100-36}}6\\\\x_1=\dfrac{-10+\sqrt{64}}6=\dfrac{-10+8}6=-\dfrac13\,,\qquad x_2=\dfrac{-10-8}6=-3</h3>
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3 years ago
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