1st Avenue would be more difficult because it’s rise and run is for every one foot forward it is 3 feet up. Meanwhile avenue 16th would start at (3,1) and the rise and run would be for every 3 feet it would go up 1 foot.
Answer: equation of the tangent plane is z = 1
Step-by-step explanation:
Given equation
z = e^(-x²-y²) at point (0,0,1)
now let z = f(x,y)
Δf(x,y) = [ fx, fy ]
= (-2xe^(-x²-y²)), (-2ye^(-x²-y²))
now
Δf (0,0) = [ 0, 0 ] = [ a, b ]
equation of the tangent plane therefore will be
z - z₀ = a(x-x₀) + b(y-y₀)
z - 1 = 0(x-0) + 0(y-0)
z - 1 = 0 + 0
z = 1
Therefore equation of the tangent plane is z = 1
Answer:
69a+6
Step-by-step explanation:
Distribute the 6 over the (10a+1) then you get 60a+6. Add the 9a to the 60 giving u 69a then you have the 6 left over making the answer 69a+6
First we should figure out how many times 2 goes into 69,(because each tile is 2 feet long) and I am going to do that by dividing 69 by 2. I got 34.5, so we can just say 35 to make it easier. So we now know we need 35 tiles, but they come in boxes of 6, so we will need to divide 35 by 6. It didn't make a full number (it was 5.833) but we need a full number of tiles so we will round up.
Our final number of how many boxes of tiles is 6.
Answer:
7.5 seconds
Step-by-step explanation:
Thus, the time required for the object to return to its point of departure is 7.5 seconds.
