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Given:
Dimensions of a tank are 50 cm by 32 cm by 20 cm
The tank is full of water and sand
Ratio of volume of water to the volume of sand is 5:1
To find:
Volume of water in the tank in liters
Solution:
Without loss of generality, let,
Length of tank = 50 cm
Breadth of tank = 32 cm
Height of tank = 20 cm
Then, we have,
Total Volume of the tank = Length * Breadth * Height
Total Volume = 50*32*20 cc
Total Volume = 32000 cc
It is given that,
Volume of water : Volume of sand = 5:1
(Volume of water)/(Volume of sand) = 5/1
Cross multiplying, we have,
Volume of sand = (Volume of water)/5
It is also given that the tank is full of water and sand. This implies that,
Volume of water + Volume of sand = Total Volume
Using the value, we obtained, we get,
Volume of water + (Volume of water)/5 = Total Volume
(6 * Volume of water)/5 = Total Volume
Plugging in the value of total volume, we get,
(6 * Volume of water)/5 = 32000 cc
Volume of water =
cc
Volume of water
26,666.6667 cc
We know that,
1 cc = 0.001 liters
26,666.6667 cc = (26666.6667 * 0.001) liters
26,666.6667 cc
26.667 liters
Thus, Volume of water in the tank is approximately 26.667 liters
Final Answer:
Volume of water in the tank (in liters) is approximately 26.667 liters
Given :
Rain is falling at 0.5 inches per hour and 1.5 inches have already accumulated.
To Find :
How many hours must have passed if there are 5 inches of rain .
Solution :
Let , after x hours rain accumulated is 5 inches .
We know , general equation of line :
y = mx +c
Here , m = 0.5 and c = 1 .
So , equation of rain accumulated is :
Now , putting value of x = 5 hours .
We get :
Hence , this is the required solution .