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1 year ago

10

Part B

1 answer:

slavikrds [6]1 year ago

3 0

Career refers to a line of work that a person chooses to commit to for long period of time.

<h3>What is a career?</h3>

The term career refers to a line of work that a person chooses to commit to for long period of time. Career becomes an important part of the life of a person.

There are two careers that interest me;

(i) Teaching

(ii) Researcher

I love teaching because it helps me to share what I know and help others to attain the same knowledge goals as I have attained. Also, I love being a research because I can join in seeking for new knowledge that could solve problems and better the life of humanity.

Learn more about career:brainly.com/question/2160579

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Math 100 points ill give brainliest as well

Lelechka [254]

Answer:

it is the answer. let me do research and I will get answer

8 0

2 years ago

Read 2 more answers

If f (x) = x + 7 and g (x) = StartFraction 1 Over x minus 13 EndFraction, what is the domain of (f circle g) (x)?

Rashid [163]

Answer:

R-{13}

Step-by-step explanation:

We are given that

$f(x)=x+7$

$g(x)=\frac{1}{x-13}$

We have to find the domain of fog(x).

$fog(x)=f(g(x))$

$fog(x)=f(\frac{1}{x-13})$

$fog(x)=\frac{1}{x-13}+7=\frac{1+7x-91}{x-13}=\frac{7x-90}{x-13}$

Domain of f(x)=R

Because it is linear function.

Domain of g(x)=R-{13}

Because the g(x) is not defined at x=13

fog(x) is not defined at x=13

Therefore, domain of fog(x)=R-{13}

6 0

2 years ago

Read 2 more answers

I need help..... please

Bogdan [553]

Answer:

Step-by-step explanation:

I would say Town residents

5 0

2 years ago

A resident of Bayport claims to the City Council that the proportion of Westside residents

Kazeer [188]

Answer:

The test statistics is $z = -1.56$

The p-value is $p-value = 0.05938$

Step-by-step explanation:

From the question we are told

The West side sample size is $n_1 = 578$

The number of residents on the West side with income below poverty level is $k = 76$

The East side sample size $n_2=688$

The number of residents on the East side with income below poverty level is $u = 112$

The null hypothesis is $H_o : p_1 = p_2$

The alternative hypothesis is $H_a : p_1 < p_2$

Generally the sample proportion of West side is

$\^{p} _1 = \frac{k}{n_1}$

=> $\^{p} _1 = \frac{76}{578}$

=> $\^{p} _1 = 0.1315$

Generally the sample proportion of West side is

$\^{p} _2 = \frac{u}{n_2}$

=> $\^{p} _2 = \frac{112}{688}$

=> $\^{p} _2 = 0.1628$

Generally the pooled sample proportion is mathematically represented as

$p = \frac{k + u}{ n_1 + n_2 }$

=> $p = \frac{76 + 112}{ 578 + 688 }$

=> $p =0.1485$

Generally the test statistics is mathematically represented as

$z = \frac{\^ {p}_1 - \^{p}_2}{\sqrt{p(1- p) [\frac{1}{n_1 } + \frac{1}{n_2} ]} }$

=> $z = \frac{ 0.1315 - 0.1628 }{\sqrt{0.1485(1-0.1485) [\frac{1}{578} + \frac{1}{688} ]} }$

=> $z = -1.56$

Generally the p-value is mathematically represented as

$p-value = P(z < -1.56 )$

From z-table

$P(z < -1.56 ) = 0.05938$

So

$p-value = 0.05938$

3 0

3 years ago

Q6: Which is the graph of the polar equation r=1/1-sin theta.

AveGali [126]

Answer:

The correct answer is C.

Step-by-step explanation:

The given equation is;

$r=\frac{1}{1-\sin(\theta)}$

This implies that;

$r(1-\sin(\theta)=1$

$r-r\sin(\theta)=1$

Let us write in Cartesian coordinates by substituting;

$r=\sqrt{x^2+y^2} ,y=r\sin(\theta)$

$\sqrt{x^2+y^2}-y=1$

$\sqrt{x^2+y^2}=y+1$

Square both sides;

$(\sqrt{x^2+y^2})^2=(y+1)^2$

This implies that;

$x^2+y^2=y^2+2y+1$

$x^2=2y+1$

$y=\frac{1}{2}x^2-\frac{1}{2}$

This is an equation of a parabola that opens upwards with a y-intercept of $-\frac{1}{2}$ .

The correct choice is C

4 0

3 years ago