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4vir4ik [10]
2 years ago
10

Part B

Mathematics
1 answer:
slavikrds [6]2 years ago
3 0

Career refers to a line of work that a person chooses to commit to for long period of time.

<h3>What is a career?</h3>

The term career refers to a line of work that a person chooses to commit to for long period of time. Career becomes an important part of the life of a person.

There are two careers that interest me;

(i) Teaching

(ii) Researcher

I love teaching because it helps me to share what I know and help others to attain the same knowledge goals as I have attained. Also, I love being a research because I can join in seeking for new knowledge that could solve problems and better the life of humanity.

Learn more about career:brainly.com/question/2160579

#SPJ1

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Debra can run 20.5 miles in 2.5 hours how many miles per hour can she run math problems
pashok25 [27]
She can run 20.5/2.5 equaling 8.2mph
7 0
4 years ago
A line contains the points (82, −96) and (87, −86) .
mezya [45]

Answer:

slope = 2

Step-by-step explanation:

Calculate the slope m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (82, - 96) and (x₂, y₂ ) = (87, - 86)

m = \frac{-86+96}{87-82} = \frac{10}{5} = 2

3 0
3 years ago
How do I divide 2 divided 898
nalin [4]
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4 0
3 years ago
Read 2 more answers
The equation of line p is y= -7/8x + 3/2. line q is parallel to line p. what is the slope of line q?
zimovet [89]

Answer:

-7/8

Step-by-step explanation:

If two lines are parallel, they have the same slope. The slope of p is -7/8 (y=mx+b), so the slope of q is also -7/8.

4 0
3 years ago
The equation h(t)=−16t2+19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff.
zhuklara [117]

\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ h(t)=-16t^2+\stackrel{\stackrel{v_o}{\downarrow }}{19}t+110~\hspace{10em}19~\frac{ft}{sec}

3 0
3 years ago
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