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2 years ago

Situation:

Mathematics

1 answer:

Nat2105 [25]2 years ago

3 0

Answer:

${ \bf{A=(P + \frac{r}{100} ) {}^{n} }} \\ { \tt{ = (4000 + \frac{5.5}{100} ) {}^{15} }} \\ \\ { \tt{ = \: 1.074 \times {10}^{54} \: dollars}}$

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Please help! 25 points is the best i can do rn :)

Ede4ka [16]

Answer

(8+6divided by 2)+4

Step-by-step explanation:

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2 years ago

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8. Solve the following equation. w - 2 = - 3

Alina [70]

Answer:

c. w = -1

Step-by-step explanation:

you have to add 2 with -3 and you get -1.

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2 years ago

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The campers in cabin A walked 1/4 of the way to otter ridge (13 miles) How many miles did they walk?

shusha [124]

The question demands that we find a fraction of a given quantity.

The 'of ' means multiplication.

So the total distance of the journey was

$13 \: miles$

But they walked ¼ of the whole journey. We are supposed to find

$\frac{1}{4} \: of \: 13 \: miles$
$\\= \frac{1}{4} \times 13 \: miles$

$= \frac{13}{4} \: miles$

$= 3.25\: miles$

Hence they walked 3.25 miles.

3 0

3 years ago

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .