Answer:
The equations that represent the reflected function are


Step-by-step explanation:
The correct question in the attached figure
we have the function

we know that
A reflection across the y-axis interchanges positive x-values with negative x-values, swapping x and −x.
therefore

The reflection of the given function across the y-axis will be equal to
(Remember interchanges positive x-values with negative x-values)

An equivalent form will be
![f(x)=5(\frac{1}{5})^{(-1)(x)}=5[(\frac{1}{5})^{-1})]^{x}=5(5)^{x}](https://tex.z-dn.net/?f=f%28x%29%3D5%28%5Cfrac%7B1%7D%7B5%7D%29%5E%7B%28-1%29%28x%29%7D%3D5%5B%28%5Cfrac%7B1%7D%7B5%7D%29%5E%7B-1%7D%29%5D%5E%7Bx%7D%3D5%285%29%5E%7Bx%7D)
therefore
The equations that represent the reflected function are


Answer:
9
Step-by-step explanation:
let a = 2
b = 5
2a + b
Substituting the values,
=> 2(2) + 5
=> 4 + 5
=> 9
Answer:
1 10/12
Step-by-step explanation:
Take the fractions and get them to the same bottom number, 12. So it would be 5 4/12 - 3 6/12.
Take 1 away from 5 to get 4 and the one you pulled would be 12/12(also equal to 1). 4 16/12 - 3 6/12 would be 1 10/12