Answer:
<em>The age at which both companies charge the same premium is 44 years</em>
Step-by-step explanation:
<u>Graph Solution to System of Equations</u>
One approach to solving systems of equations of two variables is the graph method.
Both equations are plotted in the same grid and we find the intersection point(s) of both graphs. Those are the feasible solutions.
The annual premium p as a function of the client's age a for two companies are given as:
Company A: p= 2a+24
Company B: p= 2.25a+13
The graphs of both functions are shown in the image below.
The red line indicates the formula for Company A and the blue line indicates the formula for Company B.
It can be seen that both lines intersect in the point with approximate coordinates of (44,112).
The age at which both companies charge the same premium is 44 years
150/4 = 37.5cm. You divide by four because there are four sides on a rectangle. But 37.5 is the cm of a square. Since it says one of the sides is 15cm greater, you subtract 37.5 - 15 = 27.5cm on 2 of the width. While the other 2 lengths are greater than the width by 15 cm, so you add 15 to 37.5 which gives you 52.5cm. So the 2 width are 27.5cm and the length is 52.5cm.
Answer:
y=3x+4
idk what it has to be equivalent to...I just put it in y-intercept form
Step-by-step explanation:
C=300+1200x-100x. Find x if the total cost is 3,000
3,000 = 300 + 1200x -100x
3000 = 300 + 1100x
2700 = 1100x
2700÷1100=x
x=27/11
x = 2 5/11
Round to 3
Answer:
a) 3.128
b) Yes, it is an outerlier
Step-by-step explanation:
The standardized z-score for a particular sample can be determined via the following expression:
z_i = {x_i -\bar x}/{s}
Where;
\bar x = sample means
s = sample standard deviation
Given data:
the mean shipment thickness (\bar x) = 0.2731 mm
With the standardized deviation (s) = 0.000959 mm
The standardized z-score for a certain shipment with a diameter x_i= 0.2761 mm can be determined via the following previous expression
z_i = {x_i -\bar x}/{s}
z_i = {0.2761-0.2731}/{ 0.000959}
z_i = 3.128
b)
From the standardized z-score
If [z_i < 2]; it typically implies that the data is unusual
If [z_i > 2]; it means that the data value is an outerlier
However, since our z_i > 3 (I.e it is 3.128), we conclude that it is an outerlier.
