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AlladinOne [14]
3 years ago
14

Write an equation of the form y = mx for the line shown below. If appropriate,

Mathematics
1 answer:
9966 [12]3 years ago
6 0

Answer:

y = - 0.5x

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 4, 2) and (x₂, y₂ ) = (2, - 1) ← 2 points on the line

m = \frac{-1-2}{2-(-4)} = \frac{-3}{2+4} = \frac{-3}{6} = - 0.5

The line crosses the y- axis at (0, 0 ) ⇒ c = 0

y = - 0.5x + 0 . that is

y = - 0.5x

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Step-by-step explanation:

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3 years ago
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Temka [501]

Answer:

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Step-by-step explanation:

First, make a table regarding both of the equations. You will eventually find out that both lines intersect at the point (2, 5) after you find the points on the table. From there, subtract x from both sides in the equation x + y = 2. You will      get y = -x + 2. Since they said the line was parallel, find a line that has the slope of negative one. Since we know that this line intersects the point in which the first two lines intersect, we know that the y-intercept will be 7. The equation of the line would be y=-x+7.

Multiply both sides by 2. Then, divide both sides by a to get b^2=(2P/a). Take the square root to get the value of b, which is sqrt(2P/a).

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8 0
3 years ago
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