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Svet_ta [14]
3 years ago
14

6x-9y+45 in slope intercept form

Mathematics
1 answer:
sweet [91]3 years ago
6 0
The answer is: y= 2/3x +5
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Fill in the missing monomials: 100x^2= (____)^2<br> ITS NOT 100
choli [55]

Answer:

(10x)^2

Step-by-step explanation:

4 0
3 years ago
Divde the square roots of 121 by the product of the Square roots of 25 and 4
Pavel [41]

Answer:

1.1

Step-by-step explanation:

\frac{ \sqrt{121} }{ \sqrt{25} \times  \sqrt{4}  }  =  \frac{11}{5 \times 2}  =  \frac{11}{10}  = 1.1

7 0
3 years ago
How to find left and right inverse of a 3x2 matrix.
Mnenie [13.5K]

Let A be a 3×2 matrix, L its left inverse, and R its right inverse. L and R are then matrices such that LA = I₂ (the 2×2 identity matrix) and AR = I₃ (the 3×3 identity matrix). Clearly L must be 2×3 and R must be 3×2 in order for the matrix products to be defined.

To find L and R, we start by introducing a square matrix on the the left sides of either equation above. In particular, we uniformly multiply both sides by the transpose of A, then solve for the inverse.

For the left inverse, we have

LA=I

(LA)A^\top = IA^\top

L\left(AA^\top\right) = A^\top

\left(L\left(AA^\top\right)\right)\left(AA^\top\right)^{-1} = A^\top \left(AA^\top\right)^{-1}

L\left(\left(AA^\top\right)\left(AA^\top\right)^{-1}\right) = A^\top \left(AA^\top\right)^{-1}

LI = A^\top \left(AA^\top\right)^{-1}

L = A^\top \left(AA^\top\right)^{-1}

We do the same thing for the right inverse, but take care with how we multiply both sides of AR = I₃.

AR=I

A^\top(AR)=A^\top I

\left(A^\top A\right)R = A^\top

\left(A^\top A\right)^{-1} \left(\left(A^\top A\right)R\right) = \left(A^\top A\right)^{-1} A^\top

\left(\left(A^\top A\right)^{-1} \left(A^\top A\right)\right) R = \left(A^\top A\right)^{-1} A^\top

IR = \left(A^\top A\right)^{-1} A^\top

R = \left(A^\top A\right)^{-1} A^\top

4 0
2 years ago
Simplify the following expression.<br> 2x^5+ 3x^3 - 5x^2 + x^2 +7x+1+7x^5 - 3x^3 - 4
Juli2301 [7.4K]
9x^5-4x^2+7x-3 is the simplified version of your answer.
8 0
3 years ago
Refer to the table below. of the 36 possible​ outcomes, determine the number for which the sum​ (for both​ dice) is between 7 an
frez [133]
Pairs of numbers between 1 and 6 that add up to 7: 1+6, 2+5, 3+4, 4+3, 5+2, 6+1
Pairs of numbers between 1 and 6 that add up to 8: 2+6, 3+5, 4+4, 5+3, 6+2
Pairs of numbers between 1 and 6 that add up to 9: 3+6, 4+5, 5+4, 6+3

6 for 7, 5 for 8, 4 for 9. 15 in all
7 0
3 years ago
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