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Anna35 [415]
2 years ago
11

Please I need help!!!

Mathematics
1 answer:
Valentin [98]2 years ago
7 0

Answer:

Solution given:

for second

we have

f(x)=x²-9x-36

let

y=x²-9x-36

when

x=0

y=-36

when

y=0

0=x²-9x-36

x²-12x+3x-36=0

x(x-12)+3(x-12)=0

(x-12)(x+3)=0

either

x=12

x=-3

So,

x and y intercepts are (-3,0)(12,0) and 0,-36)

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Please help. 50 points + brainliest
Korvikt [17]

Answer:

1. (a-c)\sqrt{x} + b\sqrt{y}

2. 9m + 2\sqrt{n}

3. 6a

4. (5a - 3b)\sqrt{5y}

Step-by-step explanation:

1. since a and c share the same squareroot x, you can combine these together.

2. First add like terms together. 4m - m + 6m = 9m. Then 5\sqrt{n} and -3\sqrt{n} combined equals 2\sqrt{n}

3. First simplify the square roots. squareroot of 16 is 4. square root of 49 is 7. square root of 81 is 9. They are all multiplied by a in the expression. Thus 4a - 7a + 9a = 6a

4. First simplify the radicals, they are not perfect. square root of 125 is equivalent to sqrt(25 * 5), which sqrt of 25 is 5, but we keep the sqrt of 5. For sqrt of 45, it is the same as sqrt9 * sqrt5. sqrt of 9 is the same as 3 and we keep sqrt 5. Thus we get the below:

5a\sqrt{5y} - 3b\sqrt{5y}

We can combine the two like terms and get the final answer above.

please give thanks by clicking the heart :)

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