Answer:
Considering that homeostasis is restored in the patient, his blood pH range would return to normal levels (7.35-7.45), and his hydrogen ion concentration in the blood would normalize. The effect of normalizing the body by getting rid of excess hydrogen ions is achieved by concentrating these ions into the urine for expulsion, therefore increasing the pH levels of urine.
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Explanation:
Acidosis is the condition wherein excessive acid build-up within the body causes the blood pH to become lower than normal (normal pH range 7.35-7.45). This may be due to an excessive loss of bicarbonate in the blood, also known as metabolic acidosis, or due to an impairment in the elimination of carbon dioxide in the blood from poor lung function, also known as respiratory acidosis. The body's natural response to acidosis is to increase the breathing rate to eliminate carbon dioxide in the blood, restoring the natural pH of the body.
In people with diabetes mellitus type I, the lack of insulin causes cells to breakdown fat aside from glucose as an energy source. This process produces ketones as a metabolic by-product for energy but also causes the body to be acidic. This is known as diabetic ketoacidosis.
I believe the answer is the Regeneration stage.
A this stage of the Calvin Cycle, only one of the G3P molecules leaves the cycle and is sent to the cytoplasm to contribute to the formation of other compounds needed by the plant. Because the G3P exported from the chloroplast has three carbon atoms, it takes three "turns" of the Calvin cycle to fix enough net carbon to export one G3P. Each turn makes two G3Ps, therefore three turns make six G3Ps.
Answer:
The correct answer is 3' UCA 5'
Explanation:
The rule of pairing of base-pair says that A and T base pairs with each other with two hydrogen bonds and G and C base pairs with each other with three hydrogen bonds in DNA. In the case of RNA Uracil comes at the place of thymine that means uracil replaces thymine.
Therefore according to this base-pairing rule the corresponding codon of mRNA transcribes from DNA codon 5' AGT 3' will be 3' UCA 5' as U came in place of A nucleotide, C comes in place of G nucleotide, and A comes in place of T nucleotide.
Therefore the correct answer is 3' UCA 5'.
Answer:
they produce antibodies that attach to viral surface protiens
