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AleksandrR [38]
3 years ago
6

Take the horse to overtake the

Mathematics
1 answer:
S_A_V [24]3 years ago
6 0

Answer:

  • 120 km/h

Step-by-step explanation:

  • Speed in one direction = 40 km/h
  • Speed on return = x
  • Average speed = 60 km/h

Let the distance be d

<u>Average speed </u>

  • 2d/(d/40 + d/x) = 60
  • d/40 + d/x = 2d/60
  • 1/40 + 1/x = 1/30
  • 1/x = 1/30 - 1/40
  • 1/x = (4-3)/120
  • 1/x = 1/120
  • x = 120 km/h

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Is my answer correct? // tell me if i'm wrong with details!!
Anna11 [10]

Answer:

B.

Step-by-step explanation:

This is vertical reflection, because reflections are made across vertical lines.

5 0
3 years ago
How is the series 5+11+17…+251 represented in summation notation?
NISA [10]

Answer:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

Step-by-step explanation:

Given:

  • Series 5+11+17+...+251

To find:

  • Summation notation of the given series

Summation Notation:

\displaystyle \large{\sum_{k=1}^n a_k}

Where n is the number of terms and \displaystyle \large{a_k} is general term.

First, determine what kind of series it is, there are two main series that everyone should know:

  • Arithmetic Series

A series that has common difference.

  • Geometric Series

A series that has common ratio.

If you notice and keep subtracting the next term with previous term:

  • 11-5 = 6
  • 17-11 = 6

Two common difference, we can in fact say that the series is arithmetic one. Since we know the type of series, we have to find the number of terms.

Now that brings us to arithmetic sequence, we know that first term is 5 and last term is 251, we’ll be finding both general term and number of term using arithmetic sequence:

<u>Arithmetic Sequence</u>

\displaystyle \large{a_n=a_1+(n-1)d}

Where \displaystyle \large{a_n} is the nth term, \displaystyle \large{a_1} is the first term and \displaystyle \large{d} is the common difference:

So for our general term:

\displaystyle \large{a_n=5+(n-1)6}\\\displaystyle \large{a_n=5+6n-6}\\\displaystyle \large{a_n=6n-1}

And for number of terms, substitute \displaystyle \large{a_n} = 251 and solve for n:

\displaystyle \large{251=6n-1}\\\displaystyle \large{252=6n}\\\displaystyle \large{n=42}

Now we can convert the series to summation notation as given the formula above, substitute as we get:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

5 0
2 years ago
There are two twins. One twin wants to explore the planet near Proxima Centauri and leaves on a spaceship traveling at 90% of th
miskamm [114]

Answer:

<em>4.7 years</em>

Step-by-step explanation:

Distance of planet from Earth = 1.3 parsec

We know that 1 parsec = 3.26 light years

And a light year is the distance traveled by light in time period of 1 year.

So, Distance of planet from Earth = 1.3 \times 3.26 = 4.24 light years

Given that, the person travels at a speed equal to 90% of the light speed.

To travel to the planet from Earth, Light takes 4.24 years.

To travel the distance D, at a speed s light takes time of 4.24 years.

To travel the distance D, at a speed 0.90s, the person takes time:

\dfrac{4.24}{0.90} = \bold{4.7\ years}

So, the twin on Earth ages by <em>4.7 years.</em>

7 0
3 years ago
Solve each system of equations; nonlinear algebra 2<br><br> x2 + x + y - 26 = 0<br> x + y = 1
BigorU [14]

Answer:

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\left\{\begin{array}{l}x^2+x+y-26=0\\ \\x+y=1\end{array}\right.

Solve it. First, express y in terms of x from the second equation:

y=1-x

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Apply zero product property:

x-5=0\ \text{or}\ x+5=0

So,

x=5\ \text{or}\ x=-5

When x=5, then y=1-5=-4

When x=-5, then y=1-(-5)=6

We get two solutions: (5,-4) and (-5,6)

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