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kirill115 [55]
3 years ago
5

How do I find the constant of proportionality from a equation

Mathematics
1 answer:
Scrat [10]3 years ago
7 0

Answer:The constant of proportionality k is given by k=y/x where y and x are two quantities that are directly proportional to each other. Once you know the constant of proportionality you can find an equation representing the directly proportional relationship between x and y, namely y=kx, with your specific k.

Step-by-step explanation:I didn’t know the answer sorry if it’s wrong

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Answer:

(3, -6) and (7, -6)

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Write the equation of the line perpendicular to + = that passes through (−,−). Write your answer in slope-intercept form.
Ad libitum [116K]

Answer:

y = 0.25x - 5

Step-by-step explanation:

Given line is 4x + y = 3

or y = -4x + 3

Comparing this with slope-intercept form y = mx + c :

slope of this line is -4

Product of slopes of perpendicular lines = -1

⇒ slope of a line perpendicular to this is \frac{-1}{-4} = \frac{1}{4} = 0.25

This line also passes through the point (-4,-6)

The equation of a line having slope m and passing through a point (h,k) is

y - k = m(x - h)

⇒ equation of line perpendicular to given line is y - (-6) = 0.25×{x - (-4)}

⇒ y + 6 = 0.25×(x + 4)

⇒ y + 6 = 0.25x + 1

⇒ <u>y = 0.25x - 5</u>

This is in the slope-intercept form y = mx + c with slope m = 0.25 and y-intercept (0,-5)

6 0
4 years ago
A semicircle has the radius of 2 4/5. What is its area? leave your answers in term of π
Ratling [72]

Answer:

11\dfrac{13}{25}\pi

Step-by-step explanation:

r = Radius of semicircle = 2\dfrac{4}{5}=\dfrac{24}{5}\ \text{units}

Area of semicircle is given by

A=\dfrac{\pi r^2}{2}\\\Rightarrow A=\dfrac{\pi \left(\dfrac{24}{5}\right)^2}{2}\\\Rightarrow A=\dfrac{288}{25}\pi=11\dfrac{13}{25}\pi\ \text{sq. units}

The area of the semicircle is 11\dfrac{13}{25}\pi\ \text{sq. units}.

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3 years ago
Aryonna rolls a standard number cube once. How many possible outcomes be there?
DochEvi [55]
There are six possible outcomes
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